用等式中的列表绘制一条线

Question

import matplotlib.pyplot as plt 
from math import *
f2 = open('C:\\Users\\Audrey\\Documents\\Regress1Par data.txt', 'r')
lines = f2.readlines()
f2.close()

x1 = []
y1 = []
z1 = []

for line in lines:
    p = line.split()
    x1.append(float(p[0]))
    y1.append(float(p[1]))
    z1.append(float(p[2]))

plt.scatter(x1, y1)
yerr=z1
plt.errorbar(x1,y1,yerr=yerr, fmt='o')
plt.plot(2.53+9.33(x) for x in x1)
plt.show()

我收到错误＆＃34;输入错误：＆＃39;浮动＆＃39;对象不可调用＆＃34; 如何用x1绘制这一行呢？

Answer 1

问题是你在这里缺少一个操作员：

plt.plot(2.53+9.33(x) for x in x1)

您需要使用

plt.plot(2.53+9.33*(x) for x in x1)

因为9.33（）不是可调用函数：

 >>> 2.59+9.33(x)
Traceback (most recent call last):
  File "<pyshell#24>", line 1, in <module>
    2.59+9.33(x)
TypeError: 'float' object is not callable