Question

这部分用于通过API收集我的数据。

foreach($result['List'] as $feedback)
{
    $date = date_create();
    $date_entered = $feedback['DateEntered'];
    $time = preg_replace('/[^0-9]/','',$date_entered);
    //$comment = $feedback['Text'];
    $ListingId = $feedback['ListingId'];
    $BuyNowPrice = $feedback['BuyNowPrice'];
    $max_bid = $feedback['MaximumBidAmount'];
    $SellerId = $feedback['SellerId'];
    echo '<div>' . "Seller ID: $SellerId" . " has sold one $ListingId for " . '$' . "$BuyNowPrice" . '</div>';
    echo "<div>Feedback created at " . $time . "</div>";
    echo '<br>';
}

这部分是我在检索它们之后直接插入到我的结果中的代码。

            <?php

   $dbhost = 'localhost';
   $dbuser = 'root';
   $dbpass = 'password';
   $conn = mysql_connect($dbhost, $dbuser, $dbpass);

   if(! $conn )
   {
      die('Could not connect: ' . mysql_error());
   }

   $sql = 'INSERT INTO tmfeedback '.
      '(SellerId,ListingId,BuyNowPrice) '.
      'VALUES ('.$SellerId.', '.$ListingId.', '.$BuyNowPrice.'))';

   mysql_select_db('dctdb3');
   $retval = mysql_query( $sql, $conn );

   if(! $retval )
   {
      die('Could not enter data: ' . mysql_error());
   }

   echo "Entered data successfully\n";

   mysql_close($conn);


            ?>

只有一个数据被插入数据库，它是最后显示的数据。我想知道如何更改我的代码，以便我可以同时插入所有数据而不重复？谢谢你的帮助。

Answer 1

确保您的第二个代码块位于第一个代码块内（将第二个块放在右大括号上方）。然后，它将在foreach循环的每次迭代（每个结果）中发生，并为每个迭代插入一条记录。

Answer 2

您无法将数组插入数据库，因此将查询放在循环中。这个thread可能对您有所帮助。

Answer 3

将插入放入循环内。否则，变量只具有在循环的最后一次迭代中设置的最后一个值。

<?php

$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = 'password';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);

if(! $conn ) {
    die('Could not connect: ' . mysql_error());
}
mysql_select_db('dctdb3');

foreach($result['List'] as $feedback) {
    $date = date_create();
    $date_entered = $feedback['DateEntered'];
    $time = preg_replace('/[^0-9]/','',$date_entered);
    //$comment = $feedback['Text'];
    $ListingId = $feedback['ListingId'];
    $BuyNowPrice = $feedback['BuyNowPrice'];
    $max_bid = $feedback['MaximumBidAmount'];
    $SellerId = $feedback['SellerId'];
    echo '<div>' . "Seller ID: $SellerId" . " has sold one $ListingId for " . '$' . "$BuyNowPrice" . '</div>';
    echo "<div>Feedback created at " . $time . "</div>";
    echo '<br>';

    $sql = 'INSERT INTO tmfeedback '.
        '(SellerId,ListingId,BuyNowPrice) '.
        'VALUES ('.$SellerId.', '.$ListingId.', '.$BuyNowPrice.'))';
    $retval = mysql_query($sql);
    if(! $retval ) {
        die('Could not enter data: ' . mysql_error());
    }

}

echo "Entered data successfully<br>";
mysql_close($conn);

将多个结果插入数据库PHP

3 个答案: