Question

我有一个应用程序，如果单击状态，则返回州缩写。我想在应用程序中放置一个用户消息，该消息需要实际的州名而不是缩写。

如果我点击纽约州，我有＆＃34; NY＆＃34;存储在名为data.name的变量中。如何使用此数据来获取基于其缩写的状态的全名？

我在考虑使用

var getStateInfo = function (abbrev, stateName) {

}

但我不确定我会把这个功能放进去。我也知道可能有更好的方法。任何帮助都会很棒。谢谢！

Answer 1

You can use a javascript object as a dictionary:

var states = {"NY":"New York", "NJ":"New Jersey"};

and access them like this:

alert(states["NY"]);

so your function that returns the full state name would work like this:

var getStateFullName = function (stateAbbr) {
  return states[stateAbbr];
}

Answer 2

Could you use a case statement? Have it check data.name, and return the appropriate case? Ex. Switch(data.name) Case 0 (data.name == "NY") return "New York"

Answer 3

我有打字稿（可以很容易地修改为js）功能。将美国州的缩写转换为全名，反之亦然

export default function convertUsStateAbbrAndName(input: string): string | null {
  const toAbbr = input.length !== 2;

  const states = [
    ['Alabama', 'AL'],
    ['Alaska', 'AK'],
    ['American Samoa', 'AS'],
    ['Arizona', 'AZ'],
    ['Arkansas', 'AR'],
    ['Armed Forces Americas', 'AA'],
    ['Armed Forces Europe', 'AE'],
    ['Armed Forces Pacific', 'AP'],
    ['California', 'CA'],
    ['Colorado', 'CO'],
    ['Connecticut', 'CT'],
    ['Delaware', 'DE'],
    ['District Of Columbia', 'DC'],
    ['Florida', 'FL'],
    ['Georgia', 'GA'],
    ['Guam', 'GU'],
    ['Hawaii', 'HI'],
    ['Idaho', 'ID'],
    ['Illinois', 'IL'],
    ['Indiana', 'IN'],
    ['Iowa', 'IA'],
    ['Kansas', 'KS'],
    ['Kentucky', 'KY'],
    ['Louisiana', 'LA'],
    ['Maine', 'ME'],
    ['Marshall Islands', 'MH'],
    ['Maryland', 'MD'],
    ['Massachusetts', 'MA'],
    ['Michigan', 'MI'],
    ['Minnesota', 'MN'],
    ['Mississippi', 'MS'],
    ['Missouri', 'MO'],
    ['Montana', 'MT'],
    ['Nebraska', 'NE'],
    ['Nevada', 'NV'],
    ['New Hampshire', 'NH'],
    ['New Jersey', 'NJ'],
    ['New Mexico', 'NM'],
    ['New York', 'NY'],
    ['North Carolina', 'NC'],
    ['North Dakota', 'ND'],
    ['Northern Mariana Islands', 'NP'],
    ['Ohio', 'OH'],
    ['Oklahoma', 'OK'],
    ['Oregon', 'OR'],
    ['Pennsylvania', 'PA'],
    ['Puerto Rico', 'PR'],
    ['Rhode Island', 'RI'],
    ['South Carolina', 'SC'],
    ['South Dakota', 'SD'],
    ['Tennessee', 'TN'],
    ['Texas', 'TX'],
    ['US Virgin Islands', 'VI'],
    ['Utah', 'UT'],
    ['Vermont', 'VT'],
    ['Virginia', 'VA'],
    ['Washington', 'WA'],
    ['West Virginia', 'WV'],
    ['Wisconsin', 'WI'],
    ['Wyoming', 'WY'],
  ];

  // So happy that Canada and the US have distinct abbreviations
  const provinces = [
    ['Alberta', 'AB'],
    ['British Columbia', 'BC'],
    ['Manitoba', 'MB'],
    ['New Brunswick', 'NB'],
    ['Newfoundland', 'NF'],
    ['Northwest Territory', 'NT'],
    ['Nova Scotia', 'NS'],
    ['Nunavut', 'NU'],
    ['Ontario', 'ON'],
    ['Prince Edward Island', 'PE'],
    ['Quebec', 'QC'],
    ['Saskatchewan', 'SK'],
    ['Yukon', 'YT'],
  ];

  const regions = states.concat(provinces);

  let i; // Reusable loop variable

  if (toAbbr) {
    input = input.replace(/\w\S*/g, function (txt: string) {
      return txt.charAt(0).toUpperCase() + txt.substr(1).toLowerCase();
    });
    for (i = 0; i < regions.length; i++) {
      if (regions[i][0] === input) {
        return regions[i][1];
      }
    }
  } else {
    input = input.toUpperCase();
    for (i = 0; i < regions.length; i++) {
      if (regions[i][1] === input) {
        return regions[i][0];
      }
    }
  }

  return null;
}

初始来源 - github

从缩写获取州名

3 个答案: