Question

我正在尝试在文件夹中上传多个文件，但它会显示错误“您没有选择要上传的文件。”
遇到PHP错误

严重性：警告

消息：is_uploaded_file（）期望参数1为字符串，数组   给定

文件名：libraries / Upload.php

行号：412

回溯：

文件：C：\ wamp \ www \ mshaadi \ application \ controllers \ Email.php行：55   功能：do_upload

文件：C：\ wamp \ www \ mshaadi \ index.php行：293功能：require_once

控制器

$conf['upload_path'] = './images';
    $conf['allowed_types'] = 'doc|docx|pdf|jpg|gif|jpeg|png';
    $conf['max_size'] = '9999000';
    $conf['max_width'] = '1024';
    $conf['max_height'] = '768';
    $conf['overwrite'] = TRUE;
    $this->load->library('upload');
    foreach ($_FILES as $fieldname => $fileObject){
            $this->upload->initialize($conf);
        if (!empty($fileObject['name'])){
            if (!$this->upload->do_upload($fieldname)){
                $error = $this->upload->display_errors();
                print_r($error);
            }else{
                 print_r("done");
            }
        }else {
            print_r("no");
        }
    }

查看

<div class="form-group col-md-12">
        <label for="Attach"><strong>Add Attachment</strong><br></label>
        <input type="file" class="btn btn-default btn-file" name="atta[]" id="Attach" multiple="multiple"> 
</div>

Answer 1

试试这个，

function upload_files()
{       
    $config = array();
    $config['upload_path'] = './Images/';
    $config['allowed_types'] = 'gif|jpg|png';
    $config['max_size']      = '0';
    $config['overwrite']     = FALSE;

    $this->load->library('upload');

    $files = $_FILES;
    for($i=0; $i< count($_FILES['userfile']['name']); $i++)
    {           
        $_FILES['userfile']['name']= $files['userfile']['name'][$i];
        $_FILES['userfile']['type']= $files['userfile']['type'][$i];
        $_FILES['userfile']['tmp_name']= $files['userfile']['tmp_name'][$i];
        $_FILES['userfile']['error']= $files['userfile']['error'][$i];
        $_FILES['userfile']['size']= $files['userfile']['size'][$i];    

        $this->upload->initialize($config);
        $this->upload->do_upload();
    }
}

Answer 2

这是有效的

 function do_upload()
    {       
        $this->load->library('upload');

        $files = $_FILES;
        $cpt = count($_FILES['userfile']['name']);
        for($i=0; $i<$cpt; $i++)
        {           
            $_FILES['userfile']['name']= $files['userfile']['name'][$i];
            $_FILES['userfile']['type']= $files['userfile']['type'][$i];
            $_FILES['userfile']['tmp_name']= $files['userfile']['tmp_name'][$i];
            $_FILES['userfile']['error']= $files['userfile']['error'][$i];
            $_FILES['userfile']['size']= $files['userfile']['size'][$i];    

            $this->upload->initialize($this->set_upload_options());
            $this->upload->do_upload();
        }
    }

    private function set_upload_options()
    {   
        //upload an image options
        $config = array();
        $config['upload_path'] = './Images/';
        $config['allowed_types'] = 'gif|jpg|png';
        $config['max_size']      = '0';
        $config['overwrite']     = FALSE;

        return $config;
    }

Answer 3

我将把我的答案添加为@ SachinMarwa自己答案的更全面的解释。我提交的代码不是不同的代码，而是添加了他的答案中未提及的一些行和细节。

即使看起来他的答案在技术上是正确的，也许他上面的答案也以他们自己的方式正确，但他们并不适合我。我不得不研究这个问题来找出真正发生的事情，并且我对这个过程有了足够的了解，以了解如何编写我自己的解决方案。

首先，请参阅Nana Partykar的评论，“在你的控制器中，我无法看到任何is_uploaded_file（）函数？”该评论告诉我们，人们误解了两个名称相似但文件不同的文件。我知道，因为有一段时间我认为他们必须引用同一个文件，控制器文件（名为“Uploader.php”）。我可以看到几乎所有这些问题都引用了相同的“如何使用Ajax上传多个文件”教程，包括我自己的版本。我们所使用的代码完全相同。

但是，控制器文件是“Uploader.php”。你看到$ this-＆gt; upload-＆gt; do_upload（）或$ this-＆gt; upload-＆gt; do_upload（'userfile'）甚至$ this-＆gt; upload-＆gt; do_upload（'files'），这个是指名为“Upload.php”的系统/库模块文件。请注意，在调用do_upload（）函数之前，您必须调用以下行：$ this-＆gt; load-＆gt; library（'upload'，$ config）;

Sachin Marwha给了我们一个循环遍历$ _FILES ['userfile']数组的for循环。假设您上传了三张图片。每个$ _FILES ['userfile']元素本身由5个“属性”组成：name，type，tmp_name，error，size。您可以在PHP上看到这些$ _FILE属性。

您只想一次将一个文件传递给do_upload（）。您不希望一次将所有三个（甚至20个）文件传递给do_upload。这意味着在调用do_upload（）之前，必须将$ _FILES ['userfile']数组分解为单个文件。为此，我创建$ _FILES数组的$ _FILES ['f']元素。我通过在do_upload（$ file ='userfile'）函数中的system / library / Upload.php文件中设置断点来解决这个问题，看看我在哪里得到了臭名昭着的“没有选择要上传的文件”的人（包括我自己）一直在抱怨。您会发现，该函数使用表单发送给控制器的原始$ _FILES数组。但它实际上只使用表单中输入type = file的名称。如果您没有告诉它表单输入的名称，它将默认为$ _FILES ['userfile']。事实证明，这是我最大的问题，因为如果我使用输入字段的名称，那么该字段传递数组或文件集合，而不仅仅是单个文件。所以我必须制作一个特殊的$ _FILES ['f]元素，并且只传递$ _FILES ['f']。

这就是我这样做的方式，相信我，我尝试了本页面上的所有版本以及其他版本，不仅仅是一个StackOverflow，还有其他教程：

    $cpt = count($_FILES['userfile']['name']);
    for($i=0; $i < $cpt; $i++)
    {
        unset($config);
        $config = array();
        $config['upload_path']   = $path;
        $config['allowed_types'] = 'gif|jpg|png';
        $config['max_size'] = '1000';
        $config['overwrite'] = TRUE;
        $config['remove_spaces'] = FALSE;
        $config['file_name'] = $_FILES['userfile']['name'][$i];

        // Create a new 'f' element of the $_FILES object, and assign the name, type, tmp_name, error, and size properties to the corresponding 'userfile' of this iteration of the FOR loop.
        $_FILES['f']['name'] =  $_FILES['userfile']['name'][$i];
        $_FILES['f']['type'] = $_FILES['userfile']['type'][$i];
        $_FILES['f']['tmp_name'] = $_FILES['userfile']['tmp_name'][$i];
        $_FILES['f']['error'] = $_FILES['userfile']['error'][$i];
        $_FILES['f']['size'] = $_FILES['userfile']['size'][$i];

        $this->load->library('upload', $config);
        $this->upload->initialize($config);            
        if (! $this->upload->do_upload('f'))
        {
            $data['errors'] = $this->upload->display_errors();
        }
        else
        {
            $data['errors'] = "SUCCESS";
        }

        unset($config);
        $config = array();
        $config['image_library']    = 'gd2';
        $config['source_image']     = $path . $_FILES['userfile']['name'][$i];
        $config['create_thumb']     = TRUE;
        $config['maintain_ratio']   = TRUE;
        $config['thumb_marker']     = '.thumb';
        $config['width']            = 100;
        $config['height']           = 100;

        $this->load->library('image_lib', $config);
        $this->image_lib->clear();
        $this->image_lib->initialize($config);
        $this->image_lib->resize();
        $types = array('.jpg');
    }

在for i循环中取消设置$ config数组，然后重新创建$ config数组，这就是为每个图片文件制作缩略图图像的部分。

完整的控制器上传功能：

    public function upload_asset_photo()
    {
        $data = array();
        $dateArray = explode("/",$this->input->post('date'));
        $date = $dateArray[2] . "/" . $dateArray[0] . "/" . $dateArray[1]; // year/month/day
        $cid = $this->config->item('cid'); // this is a special company id I use, unnecessary to you guys.
        $padded_as_id = sprintf("%010d", $this->uri->segment(3)); // this makes an "asset id" like "3" into "0000000003"
        $path = 'properties_/' . $padded_as_id . '/' . $date . '/'; // file path
        if (!is_dir($path)) {
            mkdir($path,0755,true); //makes the ile path, if it doesn't exist
        }

        $cpt = count($_FILES['userfile']['name']);
        for($i=0; $i < $cpt; $i++)
        {
            unset($config);
            $config = array();
            $config['upload_path']   = $path;
            $config['allowed_types'] = 'gif|jpg|png';
            $config['max_size'] = '1000';
            $config['overwrite'] = TRUE;
            $config['remove_spaces'] = FALSE;
            $config['file_name'] = $_FILES['userfile']['name'][$i];

            $_FILES['f']['name'] =  $_FILES['userfile']['name'][$i];
            $_FILES['f']['type'] = $_FILES['userfile']['type'][$i];
            $_FILES['f']['tmp_name'] = $_FILES['userfile']['tmp_name'][$i];
            $_FILES['f']['error'] = $_FILES['userfile']['error'][$i];
            $_FILES['f']['size'] = $_FILES['userfile']['size'][$i];

            $this->load->library('upload', $config);
            $this->upload->initialize($config);            
            if (! $this->upload->do_upload('f'))
            {
                $data['errors'] = $this->upload->display_errors();
            }
            else
            {
                $data['errors'] = "SUCCESS";
            }

            unset($config);
            $config = array();
            $config['image_library']    = 'gd2';
            $config['source_image']     = $path . $_FILES['userfile']['name'][$i];
            $config['create_thumb']     = TRUE;
            $config['maintain_ratio']   = TRUE;
            $config['thumb_marker']     = '.thumb';
            $config['width']            = 100;
            $config['height']           = 100;

            $this->load->library('image_lib', $config);
            $this->image_lib->clear();
            $this->image_lib->initialize($config);
            $this->image_lib->resize();
            $types = array('.jpg');
        }        

        header('Content-Type: application/json');
        echo json_encode($data);
    }

Answer 4

这应该有效

public function add()
{

    $config = array();
    $config['upload_path'] = './assets/uploaded_images';
    $config['allowed_types'] = 'gif|jpg|png';
    $config['max_size'] = '10000';

    $this->load->library('upload');
    $image_names = array();
    $files = $_FILES;

    if (isset($_FILES['images'])) {
        for ($i = 0; $i < count($_FILES['images']['name']); $i++) {
            $_FILES['image']['name'] = $files['images']['name'][$i];
            $_FILES['image']['type'] = $files['images']['type'][$i];
            $_FILES['image']['tmp_name'] = $files['images']['tmp_name'][$i];
            $_FILES['image']['error'] = $files['images']['error'][$i];
            $_FILES['image']['size'] = $files['images']['size'][$i];

            $this->upload->initialize($config);
            $image_names[$i] = $_FILES['image']['name'];
            $this->upload->do_upload('image');

        }
        $data1['images'] = implode(',', $image_names);
        $data1['productId'] = $this->input->post('productId');
        $image_id = $this->Image_model->add_image($data1);
        redirect('image/index');

    } else {
        $error = array('error' => $this->upload->display_errors());
        $this->load->model('Product_model');
        $data['all_products'] = $this->Product_model->get_all_products();
        $data['error'] = $error;
        $data['_view'] = 'image/add';
        $this->load->view('layouts/main', $data);}

}

CodeIgniter多文件上传不起作用

4 个答案: