Question

我正在使用codeigniter。我想在表单中上传带有两个文件输入字段的文件。我的代码正确地上传了我的目录中的文件，但是在模型函数参数中没有geting文件名。

我的代码

$config['upload_path'] = './uploads';
$config['allowed_types'] = 'jpg|png|jpeg|gif';
$config['max_size'] = '0';
$config['encrypt_name'] = True;

$up=$this->load->library('upload', $config);
$fileNameheaderimage = $this->upload->data();

$config2['upload_path'] = './uploads';
$config2['allowed_types'] = 'jpg|png|jpeg|gif';
$config2['max_size'] = '0';
$config2['encrypt_name'] = True;

$up2=$this->load->library('upload', $config2);
$fileNameprofileimage = $this->upload->data();

if (!$this->upload->do_upload('headerimage') || !$this->upload->do_upload('profileimage') )
{
        $status = "0";
        $msg = "File upload failed";
} 
else 
{


    $result = $this->api_model->updateprofileinfo($fileNameheaderimage['file_name'],$fileNameheaderimage['file_name']);
    if($result)
    {
        $status = "1";
        $msg = "File uploaded";
    }
    else 
    {
        $status = "0";
        $msg = "File upload failed";
    }


}

此处文件名为空

$this->api_model->updateprofileinfo($fileNameheaderimage['file_name'],$fileNameheaderimage['file_name']);

Answer 1

无需再次加载upload库$this->load->library('upload');使用initilize()方法更改配置

$this->upload->initialize($config)
//and 
$this->upload->initialize($config2)

在你的情况下，第一个配置用第二个配置覆盖所以它不起作用，试试这个

$this->load->library('upload');

$this->upload->initialize($config)
$status1 = true; $status2 = true;
if (!$this->upload->do_upload('headerimage') )
{
        $status1 = "0";
} 

$this->upload->initialize($config2)
if(!$this->upload->do_upload('profileimage'){
        $status2 = "0";
}
if($status1 == true || $status2 == true){
   $msg = "File uploaded";
}else{
   $msg = "File not uploaded";
}

codeigniter文件上传无法正常工作

1 个答案: