Question

我正在尝试解决一个需要我编写一个函数的练习，该函数将一个整数作为输入，然后返回一个tribonacci项列表直到输入值。我大部分时间都“成功”，但也会输出一个额外的术语。这是我的代码：

def tribonacci(m):
    tribs = [0, 0, 1]
    if m == 0 or m == 1:
        tribs = [0, 0]
    elif m == 2:
        tribs = [0, 0, 1]
    else:
        while tribs[-1] < m:
            tribs.append(tribs[-1] + tribs[-3] + tribs[-2])
    return tribs

我知道问题是while循环运行额外的迭代，因为最后一个元素仍然不大于m。但是，我无法立即看到如何解决这个问题。我会采用while-else循环，但我希望看到其他一些建议。

Answer 1

只需将即将生成的术语与m进行比较，如下所示：

def tribonacci(m):
    tribs = [0, 0, 1]
    if m == 0 or m == 1:
        tribs = [0, 0]
    elif m == 2:
        tribs = [0, 0, 1]
    else:
        while tribs[-1] + tribs[-3] + tribs[-2] < m:
            tribs.append(tribs[-1] + tribs[-3] + tribs[-2])

    return tribs

将tribonnacci系列返回到数字的函数

1 个答案: