Question

我有一个字典转储为csv，如下所示。我如何将其转换为数据帧 X，Y，SN作为标题？我正在考虑编写for循环并使用split 但它似乎并不优雅也没有效率......

"49,42",001C0BA79A44
"49,43",001C0BA79A46
"49,40",001C0BA79A40
"49,41",001C0BA79A42
"67,22",001C0BA791E8
"65,31",001C0BA7991E
"67,23",001C0BA793BA
"64,25",001C0BA79416
"74,29",001C0BA79354
"65,33",001C0BA79922
"58,12",001C0BA78B2D
"65,32",001C0BA79920
"72,36",001C0BA79E08
"49,31",001C0BA79525
"65,51",001C0BA7A834
"62,46",001C0BA7A729
"49,30",001C0BA79523
"66,40",001C0BA79F45
"52,42",001C0BA7A07E
"58,17",001C0BA78F49
"52,40",001C0BA79A5E
"52,41",001C0BA79A60
"52,46",001C0BA7A0B8
"52,44",001C0BA7A082
"64,20",001C0BA791AD
"55,29",001C0BA7963E
"55,28",001C0BA7963C
"69,48",001C0BA7A689
"58,15",001C0BA78F45
"55,21",001C0BA79136
"55,20",001C0BA79134
"55,23",001C0BA7913A
"55,22",001C0BA79138
"55,25",001C0BA794A1
"55,24",001C0BA7949F

Answer 1

不要使用for循环，向现有数据框添加行效率不高。

def split(string):
     return string.split(',', 1)

df = pd.read_csv(file_path, header=None, names=['Cord', 'SN'])
df['X'], df['Y'] = zip(*df.Cord.map(split))
df = df[['X', 'Y', 'SN']]

请参阅文档here。

将python dict或csv文件转换为数据帧

1 个答案: