Question

我们说我有两个名单：

foo = ['hell', 'good', 'bad']
bar = ['hello', 'goodbye', 'goodness', 'badly', 'baddest']

我想通过foo排序并查看bar中的任何单词是否只匹配但包含foo，以获得类似的内容：

hell = hello
good = goodbye goodness
bad = badly baddest

Answer 1

one = ['hell','good','bad']
two = ['hello', 'goodbye', 'goodness', 'badly', 'baddest']

for a in one:
    print a,'=',
    for b in two:
        if a in b:
            print b,
    print

输出：

hell = hello
good = goodbye goodness
bad = badly baddest

Answer 2

非常简单的问题，有很多方法可以解决它。如果没有匹配项，这里的版本不会打印出“等于”行：

foo = ["hell", "good", "bad", "fail"]
bar = ["hello", "goodbye", "goodness", "badly", "baddest", "nomatch"]

for f in foo:
    matches = [b for b in bar if f in b]
    if len(matches) > 0:
        print(f,"="," ".join(matches))

输出：

hell = hello
good = goodbye goodness
bad = badly baddest

请注意，它不输出'fail'。如果您更愿意打印“失败”一词，请删除if语句。代码甚至可以减少到一行，虽然我认为这是一个非常难以理解的单行：

[print(f,"="," ".join(b for b in bar if f in b)) for f in foo]

Python - 循环列表A中包含的列表A和匹配单词

2 个答案: