Question

我制作了一个程序，用户创建两个带有CenterX和CenterY坐标，宽度和高度的自定义矩形。在用户指定这些尺寸之后，程序将显示一个矩形是否包含另一个矩形，与另一个矩形重叠，或者根本不相符。这是我的代码：

import javafx.application.Application;
import javafx.scene.Scene;
import javafx.stage.Stage;
import javafx.scene.shape.*;
import javafx.scene.text.*;
import javafx.scene.paint.Color;
import javafx.scene.layout.Pane;
import java.util.*;

public class TwoRectangles extends Application
{
   public void start(Stage stage)
   {
       Pane pane = new Pane();

       Scanner input = new Scanner(System.in);
       System.out.print("Enter the X and Y center coordinates for rectangle1: ");
       double xCord1 = input.nextDouble();
       double yCord1 = input.nextDouble();

       System.out.print("Enter the Width and Height for rectangle1: ");
       double width1 = input.nextDouble();
       double height1 = input.nextDouble();

       System.out.print("Enter the X and Y center coordinates for rectangle2: ");
       double xCord2 = input.nextDouble();
       double yCord2 = input.nextDouble();

       System.out.print("Enter the Width and Height for rectangle2: ");
       double width2 = input.nextDouble();
       double height2 = input.nextDouble();

       Rectangle rectangle1 = new Rectangle(xCord1, yCord1, width1, height1);
       Rectangle rectangle2 = new Rectangle(xCord2, yCord2, width2, height2);

       rectangle1.setFill(null);
       rectangle2.setFill(null);
       rectangle1.setStroke(Color.BLACK);
       rectangle2.setStroke(Color.BLACK);

    // Compute the 4 corners's coordinates for the rectangle
        double r1x1 = xCord1 - (width1 / 2.0);
        double r1x2 = xCord1 + (width1 / 2.0);
        double r1y1 = yCord1 + (height1 / 2.0);
        double r1y2 = yCord1 - (height1 / 2.0);

        double r2x1 = xCord2 - (width2 / 2.0);
        double r2x2 = xCord2 + (width2 / 2.0);
        double r2y1 = yCord2 + (height2 / 2.0);
        double r2y2 = yCord2 - (height2 / 2.0);


   if ((r1x1 >= r2x1) && (r1x2 <= r2x2) && (r1y1 >= r2y1) && (r1y2 <= r2y2))
      { 
         Text containText = new Text(500, 500, "One rectangle is contained in another");
         pane.getChildren().add(containText);
      }

    else if ((r1x1 < r2x2) && (r1x2 > r2x1) &&  (r1y1 < r2y2) && (r1y2 > r2y1))
       {
            Text overlapText = new Text(500, 500, "The rectangles overlap");
            pane.getChildren().add(overlapText);

       }

       else
       {
            Text noneText = new Text(500, 500, "The rectangles do not overlap");
            pane.getChildren().add(noneText);
       }      
       pane.getChildren().addAll(rectangle1, rectangle2);
       Scene scene = new Scene(pane);
       stage.setTitle("Overlapping Rectangles");
       stage.setScene(scene);
       stage.show();
   }
}

每当我输入（50,50）两个矩形的centerX和centerY坐标，宽度：20，矩形1的高度50和宽度50，矩形2的高度20它告诉我矩形在彼此内部而不是相互重叠。我做错了什么？

Answer 1

你的问题是Y坐标。第二个小于第一个。这意味着测试的可读性会降低，例如

(r1x1 >= r2x1) && (r1x2 <= r2x2) && (r1y1 >= r2y1) && (r1y2 <= r2y2)

变为（同时检查r2是否在r1中）：

(r1x1 >= r2x1 && r1x2 <= r2x2 && r1y1 <= r2y1 && r1y2 >= r2y2) ||
//                                    ^^              ^^
(r2x1 >= r1x1 && r2x2 <= r1x2 && r2y1 <= r1y1 && r2y1 >= r1y2)

矩形重叠，但说它在里面？

1 个答案: