Question

using System;
using System.IO;
using System.Text;
using System.Collections.Generic;

namespace Books
{
    abstract class Book // Class prototype for a book from a text file
    {
        public string bookTitle { get; set; } // the title
        public string bookSubTitle { get; set; } // subtitle
        public string bookAuthor { get; set; }  // author
        protected string[] bookText { get; set; } // book's text
        protected int totalPages { get; set; } // Total number of pages
        public Boolean loadError = false;     // file not found marker
        abstract internal void loadPages(); // seperates pages

        // Generic class constructor
        public Book(string filename)
        {
            if (File.Exists(filename)) // does text file book exist?
                bookText = File.ReadAllLines(filename); //load bookText
            else
            {
                loadError = true;// File was not found
                ErrorMessage("File \"" + filename + "\" is missing.                             
                  \nClosing program.");
            }
        }

        // Displays an error message
        private static void ErrorMessage(string str)
        {
            Console.ForegroundColor = ConsoleColor.Red;
            Console.WriteLine(str);
            Console.ResetColor();
        }

        // Prototype class for a page
        protected abstract class Page
        {
            internal int pageNum { get; set; }
            internal string pageText { get; set;}
        }
    }

    // Class used specifically for the "Daily Reflections" book
    class DailyReflections : Book
    {
        List<dailyPage> dailypages = new List<dailyPage>();
        private DateTime today = DateTime.Now;

        // Organizes pages from bookText[] into dailypages list
        internal void loadPages()
        {
            DateTime date = new DateTime();
            DateTime date2 = new DateTime();
            string temptitle;
            StringBuilder str = new StringBuilder();

            for (int bookline = 0; bookline < bookText.LongLength;                    
              bookline++)
            {
                if (DateTime.TryParse(bookText[bookline], out date))
                {
                    bookline++;
                    temptitle = bookText[bookline].Trim();
                    while (!DateTime.TryParse(bookText[bookline], out                         
                      date2))
                    {
                        str.AppendLine(bookText[bookline]);
                        if (++bookline >= bookText.LongLength) break;
                    }
                    bookline--;
                    dailypages.Add(new dailyPage());
                    dailypages[totalPages].pageDate = date;
                    dailypages[totalPages].pageText = str.ToString();
                    dailypages[totalPages].pageNum = totalPages + 1;
                    dailypages[totalPages].pageTitle = temptitle;
                    str.Clear();
                    totalPages++;
                }
            }
        }

        // Class constructor unique to DailyReflections
        public DailyReflections() : base("Daily Reflections.txt")
        {
            this.bookTitle = "Daily Reflections";
            this.bookSubTitle = "";
            this.bookAuthor = "";
            loadPages();
        }

        // Display all lines of bookText
        public void printText()
        {
            foreach (dailyPage txt in dailypages)
            {
                Console.WriteLine(txt);
            }
        }

        // Page[] unique to DailyReflections
        protected class dailyPage : Page
        {
            internal DateTime pageDate { get; set; }
            internal string pageTitle { get; set; }
        }
    }
}

如何在没有'datetime.timedelta'的情况下简单地返回值？在这种情况下，我想返回2200。

Answer 1

如果您只需要获取日期的差异（没有时间），那么检索days属性就足够了：

(date(1975, 10, 14) - date(1969, 10, 5)).days

如果您需要具有浮点精度的天数，那么我将使用total_seconds()计算：

(dt1 - dt2).total_seconds() / (3600*24)

Answer 2

您要找的是两个日期之间的天数距离？在这种情况下，return x.days应该可以解决问题。有关timedelta对象的更多信息，请阅读https://docs.python.org/2/library/datetime.html#timedelta-objects

使用datetime：将日期之间的差异作为整数

2 个答案: