Question

我有以下小提琴

当我的日期如下var firstDate = new Date(2008,01,12); var secondDate = new Date(2008,01,12);时，我收到的警告为0我希望显示为1，以便有人帮助我

Answer 1

我猜你想表明某事长达1天（日期相同），如果日期就像

var firstDate = new Date(2008,01,12);
var secondDate = new Date(2008,01,13);

你想表明它是2天。

那么为什么不在diff中添加1呢？（如果我低估了你的目标）

var diffDays = Math.round(Math.abs((firstDate.getTime() - secondDate.getTime())/(oneDay))) +1;

Answer 2

    function change(){
       
       var oneDay = 24*60*60*1000;
    var firstDate = new Date(2008,1,12);
    var secondDate = new Date(2008,1,12);
    
    var diffDays = Math.round(Math.abs((firstDate.getTime() - secondDate.getTime())/(oneDay)));
//to avoid 0 & less and make it 1 at least 
//===========================================
    diffDays = diffDays <= 0 ? 1 : diffDays;
//===========================================
    alert(diffDays)
        
    }

<input type="submit" id="byBtn" value="Change" onclick="change()"/>

Answer 3

如果您想要相同日期的差异，它将始终为零。为什么不应该呢？无论如何，您可以检查结果是否为 0 ，然后将其设置为1.

var diffDays = Math.round(Math.abs((firstDate.getTime() - secondDate.getTime())/(oneDay)));
diffDays=diffDays?diffDays:1;
alert(diffDays);

如果我选择两个日期作为当前日期，则获取两个日期之间的差异显示为1

3 个答案: