如何更改AJAX网址以使其从select
?
<html>
<head>
<title>Tester</title>
<link href="css/style.css" rel="stylesheet" type="text/css" />
<script type="text/javascript" src="lib/jquery-1.9.1.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#button").click(function() {
$("#loading").show();
var artikel = $("#text").val();
$.ajax({
type: "POST",
url: "<path>/test1.php", // <-- change url from listbox value test1.php / test2.php / test3.php
data: "text=" + artikel,
success: function(msg) {
$("#result").show();
$("#result").html(msg);
$("#loading").hide();
}
});
});
$("#reset").click(function() {
$("#result").html("");
});
});
</script>
</head>
<body>
<center>
<form>
<select id="listbox">
<option value="test1.php">Test 1</option>// send value to ajax url
<option value="test2.php">Test 2</option>// send value to ajax url
<option value="test3.php">Test 3</option>// send value to ajax url</select>
<br/>
<br/>
<textarea placeholder="Write your text here..." class="custom" rows="10" cols="80" name="isi" id="text"></textarea>
<br/>
<br/>
<input type="button" value="Go" class="btn-rewriter btn-rewriter-success" id="button">
<input type=reset id="reset" class="btn-clear btn-clear-success" value="Clear">
</form>
<img src="img/loading.gif" style="display:none" id="loading">
<br/>
<br/>
<div id="result" style="display:none;"></div>
</center>
</body>
</html>
答案 0 :(得分:1)
您可以使用select
阅读当前选定的val()
值,并将其附加到网址字符串:
$("#button").click(function(){
$("#loading").show();
$.ajax({
type: "POST",
url: "<path>/" + $('#listbox').val(), // < appended here
data: {
text: $("#text").val()
},
success: function(msg){
$("#result").html(msg).show();
$("#loading").hide();
}
});
});
另请注意,我将data
属性更改为对象,以便jQuery将根据需要为您编码。