我应该输入一个字符串,并将所有to
,you
,for
和&
子字符串替换为2
,{ {1}},U
和4
。
当我输入字符串"and , and,and , to , to,to , you ,you , you, for ,for , for,a , a,e , e,i , i,o , o,u , u"
时,它只会在我打印时输出and
。
public void simplify()
{
System.out.println("Enter a string to simplify: ");
String rope = in.next();
System.out.println(simplifier(rope));
}
public String simplifier(String rope)
{
rope = rope.replace(" and "," & ");
rope = rope.replace(" and"," &");
rope = rope.replace("and ","& ");
rope = rope.replace(" to "," 2 ");
rope = rope.replace(" to"," 2");
rope = rope.replace("to ","2 ");
rope = rope.replace(" you "," U ");
rope = rope.replace("you ","U ");
rope = rope.replace(" you"," U");
rope = rope.replace(" for "," 4 ");
rope = rope.replace("for ","4 ");
rope = rope.replace(" for"," 4");
rope = rope.replace("a ","");
rope = rope.replace(" a","");
rope = rope.replace("e ","");
rope = rope.replace(" e","");
rope = rope.replace("i ","");
rope = rope.replace(" i","");
rope = rope.replace(" o","");
rope = rope.replace("o ","");
rope = rope.replace("u ","");
rope = rope.replace(" u","");
System.out.print(rope);
return rope;
}
输出:and and
似乎在第一个空格
之后切断了返回的字符串我不知道发生了什么,为什么它不能正常工作。 我做错了什么?
答案 0 :(得分:1)
以下是我简化代码并获得正确结果的方法:
String rope = "and , and,and , to , to,to , you ,you , you, for ,for , for,a , a,e , e,i , i,o , o,u , u";
// rope = rope.replaceAll(" ", "");
rope = rope.replaceAll("and", "&");
rope = rope.replaceAll("to", "2");
rope = rope.replaceAll("you", "U");
rope = rope.replaceAll("for", "4");
rope = rope.replaceAll("a", "");
rope = rope.replaceAll("e", "");
rope = rope.replaceAll("i", "");
rope = rope.replaceAll("o", "");
rope = rope.replaceAll("u", "");
System.out.println(rope);
答案 1 :(得分:0)
将第一个Send("{SHIFTDOWN}{CTRLDOWN}{ALTDOWN}{+}{ALTUP}{CTRLUP}{SHIFTUP}")
替换为rope = rope.replace(" and "," & ");
现在它应该工作了。问题是您尝试替换的第一个“和”是rope = rope.replace("and "," & ");
,而不是and
,这就是为什么留下并且没有被替换的原因。
同时删除and
的第二行,即simplifier
。这是重复的,因为您已经在调用方法中打印结果。
更新: 我看到你在这里想做什么。试试这个:
对于要替换的每个单词,只需将其替换一次。因此对于System.out.print(rope);
,请执行:
and
对于rope.replace("and", "&");
,请执行:
to
不要在单词之间添加任何空格,没有必要。执行rope.replace("to", "2");
一次将替换该单词的所有次出现。