Question

我正在尝试替换以$开头的部分字符串（我手动使用String中的参数）但由于某种原因它失败了。这就是我所拥有的：

 public void sendNotificationOfAcceptedMeeting(String candidateName, DateTime dateTime) {
        Map<String,String> params = new HashMap<String,String>();
        params.put("date", dateTime.toString(DATETIME_FORMAT));
        params.put("candidate", candidateName);
        sendEmailWithTemplate(TEMPLATE_ALL_ACCEPTED, params);
    }

然后：

private void sendEmailWithTemplate(String templateName, Map<String, String> params) {
    EmailTemplate template = emailTemplateDao.getEmailTemplate(templateName);
    String subject = applyTemplateParameters(template.getSubject(), params);
    String body = applyTemplateParameters(template.getTetxBody(), params);
    sendEmail(subject, body);
}

最后：

private String applyTemplateParameters(String templateText, Map<String, String> params) {
    String toReturn = templateText;
    if (params != null) {
        System.out.println("map size: " + params.size());
        for (Entry<String, String> entry : params.entrySet()) {
            System.out.println("********************");
            System.out.println(toReturn + "   ***BEFORE");
            toReturn.replace("$" + entry.getKey(), entry.getValue());
            System.out.println("$" + entry.getKey() + "  ***KEY");
            System.out.println(entry.getValue() + " ***VALUE");
            System.out.println(toReturn + "   AFTER");
        }
    }
    return toReturn;
}

正如您可能想到的那样，第二个方法使用我想要修改的String调用第三个方法，并映射参数及其值。第二种方法将template String的路径设置为：

    The meeting request at $date with $candidate was accepted by all interviewers.

然而，第三种方法中的sysouts打印：

    map size: 2
********************
The meeting request at $date with $candidate was 
accepted by all interviewers.   ***BEFORE
$candidate  ***KEY
Acceeedsasd Stetfghfghasd ***VALUE
The meeting request at $date with $candidate was 
accepted by all interviewers.   AFTER
********************
The meeting request at $date with $candidate was 
accepted by all interviewers.   ***BEFORE
$date  ***KEY
27/12/2014 8:00 ***VALUE
The meeting request at $date with $candidate was 
accepted by all interviewers.   AFTER

这清楚地表明它不会替换参数...我想可能会$打破它（正则表达式）但是replace()，不像replaceAll()需要字符串 - 而不是正则表达式。我没有想法，任何帮助表示赞赏。

Answer 1

你必须这样做：

 toReturn = toReturn.replace("$" + entry.getKey(), entry.getValue());

然后打印toReturn

的值

Answer 2

尝试更换＆＃34; $＆＃34;在您的代码中使用＆＃34; \ 0024＆＃34;

像这样：

toReturn = toReturn.replace（＆＃34; \ 0024＆＃34; + entry.getKey（），entry.getValue（））;

Answer 3

问题是replace方法返回String并且没有使用它。请参阅下文，我将结果放入replacedText。

String replacedText = toReturn.replace("$" + entry.getKey(), entry.getValue());
System.out.println("$" + entry.getKey() + "  ***KEY");
System.out.println(entry.getValue() + " ***VALUE");
System.out.println(replacedText+ "   AFTER");

Answer 4

字符串是不可变的，无法替换，刚

toReturn = toReturn.replace("$...","")

String的replace（）方法存在问题

4 个答案: