Question

我正在尝试创建一个注册/登录html / php脚本。我创建了一个数据库，我相信我的html / php代码是正确的。我想知道我是否遗漏了一些小事。到目前为止，这是我的代码。

这是数据库

<?php
         error_reporting(E_ALL);
         ini_set('display_errors', 'on');
if(isset($_POST["submit"]))
        {
        $User = "**"; 
        $Password = "**";
        $Database = "member";
        $Host = "localhost"; 
        $con = mysqli_connect($Host, $User, $Password);
        if (mysqli_connect_errno())
        {
        echo "Failed to connect to MySQL: " . mysqli_connect_error();
        }

        mysqli_select_db($con,$Database);
        $myusername = $_POST["username"];
        $mypassword = $_POST["password"];
        $sql = "INSERT INTO member (username, password) VALUES ('$myusername','$mypassword')";
        mysqli_query($con,$sql);
        mysqli_commit($con);
        mysqli_close($con);

        echo "Thank You! Information entered.";
        }
else
        {
        ?>
        <form method="post" action="proInput.php">
        Username:<input type="Text" name="username"><br>
        Password:<input type="Text" name="password"><br>
        <input type="Submit" name="submit" value="Register"></form>
        <?
        }
?>

每当我在MySQL中输入SELECT * FROM member;时，我的数据库都是空的。

Answer 1

mysqli_commit($con);
mysqli_query($con,$sql);
mysqli_close($con);

您在插入之前提交，然后关闭未提交的事务。尝试在上面的摘录中交换前两行。

Answer 2

正如您在评论中已经回答的那样，

该文件的名称不是main_login.php，而是proinput.php

您的表单将其数据发布到main_login.php，我假设您在该页面上没有插入查询，您的代码根本不会运行。< / p>

选项：

尝试将此php文件的名称更改为main_login.php，然后将echo重定向到用户登录页面

将插入的这一部分移动到main_login.php

if(isset($_POST["submit"]))
    {
    $User = ""; 
    $Password = "";
    $Database = "member";
    $Host = "localhost"; 
    $con = mysqli_connect($Host, $User, $Password);
    if (mysqli_connect_errno())
    {
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }
    mysqli_select_db($con,$Database);
    $myusername = $_POST["username"];
    $mypassword = $_POST["password"];
    $sql = "INSERT INTO member (username, password) VALUES ('$myusername','$mypassword')";
    mysqli_query($con,$sql);
    mysqli_commit($con);
    mysqli_close($con);




    echo "Thank You! Information entered.";
    }
    else
    {
    ?>

用于调试在php
打开后立即将以下内容添加到php文件的最顶层
```
 error_reporting(E_ALL);
 ini_set('display_errors', 'on');
```

这对我有用

  <?php

  error_reporting(E_ALL);
  ini_set('display_errors', 'on');

  if(isset($_POST["submit"]))
    {
    $User = "db_user"; 
    $Password = "db_password";
    $Database = "db_name";
    $Host = "db_host"; 
    $con = mysqli_connect($Host, $User, $Password);
    if (mysqli_connect_errno())
    {
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }
    mysqli_select_db($con,$Database);
    $myusername = $_POST["username"];
    $mypassword = $_POST["password"];
    $sql = "INSERT INTO member (username, password) VALUES ('$myusername','$mypassword')";
    mysqli_query($con,$sql);
    mysqli_commit($con);
    mysqli_close($con);

    echo "Thank You! Information entered.";
    }
    else
    {
    ?>
    <form method="post" action="proinput.php">
    Username:<input type="Text" name="username"><br>
    Password:<input type="Text" name="password"><br>
    <input type="Submit" name="submit" value="Register"></form>
    <?php
    }
    ?>

Answer 3

请在查询结束时添加'或die（mysqli_error（））'并获取sql错误报告。这应该告诉你sql究竟是什么问题。 PHP错误报告只会出现php错误。

MySQL数据库没有填充

3 个答案: