我试图在我的mysql数据库的表中获得一个简单的数据HTML表,但它只是在页面上的一个段落中显示为混乱的文本和代码。可能导致这种情况的任何想法?以下是我正在运行的代码:
<html lang="en"><head><meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>
Title
</title>
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<!-- Bootstrap -->
<link href="./swipe_da_code_files/bootstrap.min.css" rel="stylesheet">
<link rel="icon" type="image/ico" href="http://lndapp.wpi.edu/img/favicon.ico">
<style type="text/css">
body {
padding-top: 60px;
padding-bottom: 40px;
}
</style>
</head>
<body>
<nav class="navbar navbar-inverse navbar-fixed-top">
<div class="container">
<div class="navbar-header">
<button type="button" class="navbar-toggle collapsed" data-toggle="collapse" data-target="#navbar" aria-expanded="false" aria-controls="navbar">
<span class="sr-only">Toggle navigation</span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
<a class="navbar-brand" href="http://url:Port">AdminPortal</a>
</div>
<div id="navbar" class="collapse navbar-collapse">
<ul class="nav navbar-nav">
<li class="active"><a href="default.htm">Home</a></li>
<li><a href="CreateUser.html">Create User</a></li>
<li><a href="Database.html">Database</a></li>
</ul>
</div><!--/.nav-collapse -->
</div>
</nav>
<div class="container">
<h1>Database Landing Page</h1>
</div>
<?php
$server = mysql_connect("server", "user", "password");
$db = mysql_select_db("database", $server);
$query = mysql_query("SELECT * FROM Table");
?>
<table>
<tr>
<td>username</td>
<td>password</td>
<td>physicianID</td>
</tr>
<?php
while ($row = mysql_fetch_array($query)) {
echo "<tr>";
echo "<td>".$row[username]."</td>";
echo "<td>".$row[password]."</td>";
echo "<td>".$row[physicianID]."</td>";
echo "</tr>";
}
?>
</table>
</body></html>
我尝试了各种不同的方式来显示数据,这是我能想到的最简单的表格,只是以表格形式显示几行,但它没有运行。我仔细检查了我输入的连接详细信息,以及数据库的查询,并确定不是导致它的原因。
答案 0 :(得分:2)
替换
echo "<td>".$row[username]."</td>";
echo "<td>".$row[password]."</td>";
echo "<td>".$row[physicianID]."</td>";
通过
echo "<td>".$row['username']."</td>";
echo "<td>".$row['password']."</td>";
echo "<td>".$row['physicianID']."</td>";
你缺少报价!
答案 1 :(得分:1)
请使用mysqli或PDO,因为现在不推荐使用mysl方法。
<?php
$server=mysqli_connect("server", "user", "password" , "my_db");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($server, "SELECT * FROM Table")
?>
然后
<?php
while ($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>".$row['username']."</td>";
echo "<td>".$row['password']."</td>";
echo "<td>".$row['physicianID']."</td>";
echo "</tr>";
}
?>
Akintunde007在他/她的答案中是正确的,你正在解析一个常量。