Question

这是我的作业：“编写一个函数，找到两个整数输入中较大的一个（在主程序中），但允许你使用pass by reference来改变函数中整数的值。”我一直试图找出我的代码有什么不对，但我不知道它是什么。有人请帮帮我!!这项任务今晚到期!! 这是我现在的代码：

#include <iostream>

using namespace std;

int change(int& x, int& y)

{
    int temp=0;

    cout << "Function(before change): " << x << " " << y << endl;

    temp = x;
    x = y;
    y = temp;

    cout << "Function(after change): " << x << " " << y << endl;

}

int main()

{
    int x,y;

    cout << " Please Enter your first number: ";
    cin >> x;

    cout << " Please Enter your second number: ";
    cin >> y;

    if (x > y)
        cout << x << " is greater than " << y << endl;

    if (x < y)
        cout << y << " is greater than " << x << endl;

    if (x == y)
        cout << x << " is equal to " <<y << endl;

    cout << "Main (before change): " << x << " " << y << endl;
    change(x, y);

    cout << "Main (after change): " << x << " " << y << endl;

    system("Pause");

    return 0;

}

Answer 1

change被声明为返回int，但它永远不会返回任何内容。看起来你的函数应该返回任何内容，所以只需将其声明为void：

void change(int& x, int& y)

错误：控制到达非空函数的结束？

1 个答案: