基于其他表

Question

如图所示，我有四张桌子。只有TableB和TableBChild具有外键关系。

我想在这里实现的是确定是否 TableBChild.MemberID匹配TableA.memberNo，其中TableB.isgood为真

如果不是条件不满足，则批量更新isvalid为false。

但我无法将TableBChild.MemberID与Member.MemberNo进行比较。

Update TableB
Set IsValid = 0
From TableA as A
INNER JOIN TableB as B ON A.TableBNo = B.TableBNo And IsGood = 1
INNER JOIN TableBChild as BC ON B.TableBID = BC.TableBID
                             AND BC.MEMBERID != SELECT MemberID 
                                                FROM Member 
                                                WHERE MemberNo = A.MemberNo // This line is not working

Answer 1

尝试使用NOT IN代替!=，如下所示：

Update TableB
Set IsValid = 0
From TableA as A INNER JOIN TableB as B
                      ON A.TableBNo = B.TableBNo And IsGood = 1
                 INNER JOIN TableBChild as BC
                       ON B.TableBID = BC.TableBID
AND BC.MEMBERID NOT IN ( SELECT MemberID from Member Where MemberNo = A.MemberNo )

Answer 2

更改你的最后一行：

AND BC.MEMBERID != (SELECT MemberID from Member Where MemberNo = A.MemberNo)

Answer 3

我会做什么：

UPDATE TableB
SET IsValid = 0
WHERE TableBID NOT IN 
(
-- this will select TableBID's satisfying:
-- TableB.IsGood is true, 
-- and corresponding TableBChild has memberID that exists in TableA.MemberNo
SELECT tbc.TableBID
FROM TableBChild tbc
INNER JOIN TableB tb ON tb.TableBID = tbc.TableBID
INNER JOIN TableA ta ON tbc.MemberID = ta.MemberNo
WHERE tb.IsGood = 1
)