我有以下代码......
ran_int = rand(); //check READ ME Citation B
if (input == 32){
//rand() with 2^31 as lower limit and 2^32 as its upper
long long int upper_limit = 4294967295;
long long int lower_limit = 2147483649
ran_32_64 = (rand() * 2) % (upper_limit - lower_limit);
ran_32_64 += lower_limit;
}
else if(input == 64){
//rand() x 4 with 2^63 as lower limit and 2^64 as its upper
unsigned long long int upper_limit = powl(2, 64);
long long int lower_limit = powl(2, 63);
ran_32_64 = (rand() * 4) % (upper_limit - lower_limit);
ran_32_64 += lower_limit;
}
else if(input == 128){
//rand() x 8 with 2^127 as lower limit
unsigned _int128 upper_limit =
}
对于最后一个块,我需要表示一个128位的二进制数。我知道我可以将类型_int128用于128位值,但这并不完全准确。
所以我想要完全准确我可以使用double类型,但我找不到任何有关128位双重类型的文献。
有什么想法吗?
答案 0 :(得分:2)
如果它是128b,它不是双倍的,但GNU和英特尔C / C ++编译器都通过__float128
支持128b浮点数(旧的英特尔C / C ++编译器有Quad
)。
GCC documentation非常彻底。
有库实现,包括:
很难说你的代码试图做什么,但是你之前写的128位整数等价于下面。
老实说,我不知道你打算使用任何宽度的浮点数,所以如果你想要128b浮点数的详细信息,请提供一个更合适的例子。
#include <stdint.h>
#include <stdlib.h>
#include <math.h>
#include <quadmath.h>
void foo(int input) {
int ran_int = rand(); //check READ ME Citation B
if (input == 32){
//rand() with 2^31 as lower limit and 2^32 as its upper
uint32_t upper_limit = 4294967295;
int32_t lower_limit = 2147483649;
uint32_t ran_32_64 = (rand() * 2) % (upper_limit - lower_limit);
ran_32_64 += lower_limit;
}
/*
else if(input == 64){
//rand() x 4 with 2^63 as lower limit and 2^64 as its upper
uint64_t upper_limit = powl(2L, 64);
int64_t lower_limit = powl(2L, 63);
uint64_t ran_32_64 = (rand() * 4) % (upper_limit - lower_limit);
ran_32_64 += lower_limit;
}
*/
else if(input == 128){
//rand() x 8 with 2^127 as lower limit
unsigned __int128 upper_limit = powq(2, 64);
__int128 lower_limit = powq(2, 63);
unsigned __int128 ran_32_64 = (rand() * 4) % (upper_limit - lower_limit);
ran_32_64 += lower_limit;
}
}