我正在尝试使用java.net.Socket
而不使用java.net.URL
和外部库来下载图像。这就是我所拥有的,我不确定什么是无效的。
String domain = "www.manchester.edu";
String path = "/images/default-source/default-album/slide1.jpg";
Socket socket = new Socket(domain,80);
PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(socket.getOutputStream())));
out.println("" +
"Get "+path+" HTTP/1.1\n" +
"Host: "+domain+"\n"+
"");
out.println();
out.flush();
BufferedImage image = ImageIO.read(socket.getInputStream());
要查看流中的内容,请将BufferedImage
行换成:
BufferedReader in = new BufferedReader(new InputStreamReader(socket.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null && inputLine.trim() != "0") {
System.out.println(inputLine);
}
假设ImageIO.read(...)
方法不期望套接字输入流中的HTTP标头。但我不知道如何删除标题。我尝试使用BufferedReader
读取标题行,然后将套接字输入流传递给ImageIO.read(...)
,但这不起作用。
以下是BufferedReader
打印的字符串:
HTTP/1.1 200 OK
Cache-Control: public, max-age=7776000
Content-Length: 96876
Content-Type: image/jpeg
Expires: Thu, 04 Feb 2016 21:36:46 GMT
Last-Modified: Tue, 15 Sep 2015 14:23:40 GMT
Server: Microsoft-IIS/8.5
content-disposition: inline; filename=slide1.jpg
X-AspNet-Version: 4.0.30319
X-Powered-By: ASP.NET
Date: Fri, 06 Nov 2015 21:36:46 GMT
����...
最后的不可打印字符似乎表明标题后面的内容是某种形式的图像。但是,如何将其转换为java.awt.image.BufferedImage
或javafx.scene.image.Image
?后者有一个构造函数,它接受输入流,我已经尝试过,但它不起作用(因为http头?)。这个问题与this类似,但我试图创建一个图像而不是文件。
答案 0 :(得分:2)
使用BufferedReader
是一个错误,有两个原因:
String
,然后将其转换回字节以将其发送到输出流。转换可能(并且可能会)导致数据丢失; 你需要手术接近,创建一个所需大小的字节缓冲区,并使用InputStream
按照你自己的条件逐字节读取流。此外,因为您知道HTTP标头结尾是" \ r \ n \ r \ n" (或13 10 13 10字节),您可以扫描自己的缓冲区以获得此模式,并采取相应的行动。
最好的办法是将图像下载到文件中,然后使用ImageIO从本地文件中读取图像。
// Initialize the streams.
final FileOutputStream fileOutputStream = new FileOutputStream(file);
final InputStream inputStream = socket.getInputStream();
// Header end flag.
boolean headerEnded = false;
byte[] bytes = new byte[2048];
int length;
while ((length = inputStream.read(bytes)) != -1) {
// If the end of the header had already been reached, write the bytes to the file as normal.
if (headerEnded)
fileOutputStream.write(bytes, 0, length);
// This locates the end of the header by comparing the current byte as well as the next 3 bytes
// with the HTTP header end "\r\n\r\n" (which in integer representation would be 13 10 13 10).
// If the end of the header is reached, the flag is set to true and the remaining data in the
// currently buffered byte array is written into the file.
else {
for (int i = 0; i < 2045; i++) {
if (bytes[i] == 13 && bytes[i + 1] == 10 && bytes[i + 2] == 13 && bytes[i + 3] == 10) {
headerEnded = true;
fileOutputStream.write(bytes, i+4 , 2048-i-4);
break;
}
}
}
}
inputStream.close();
fileOutputStream.close();