Question

我正在开发一个与我编写的RESTful Web服务进行通信的Android应用程序。对Volley方法使用GET非常简单，但我无法理解POST方法。

我想在请求正文中发送POST请求String，并检索网络服务的原始响应（例如200 ok，500 server error ）。

所有我能找到的是StringRequest，它不允许发送数据（正文），并且它还限制我接收解析的String响应。我还遇到JsonObjectRequest接受数据（正文）但检索解析后的JSONObject响应。

我决定编写自己的实现，但是我找不到从Web服务接收原始响应的方法。我该怎么办？

Answer 1

您可以参考以下代码（当然您可以自定义以获取有关网络响应的更多详细信息）：

try {
    RequestQueue requestQueue = Volley.newRequestQueue(this);
    String URL = "http://...";
    JSONObject jsonBody = new JSONObject();
    jsonBody.put("Title", "Android Volley Demo");
    jsonBody.put("Author", "BNK");
    final String requestBody = jsonBody.toString();

    StringRequest stringRequest = new StringRequest(Request.Method.POST, URL, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {
            Log.i("VOLLEY", response);
        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            Log.e("VOLLEY", error.toString());
        }
    }) {
        @Override
        public String getBodyContentType() {
            return "application/json; charset=utf-8";
        }

        @Override
        public byte[] getBody() throws AuthFailureError {
            try {
                return requestBody == null ? null : requestBody.getBytes("utf-8");
            } catch (UnsupportedEncodingException uee) {
                VolleyLog.wtf("Unsupported Encoding while trying to get the bytes of %s using %s", requestBody, "utf-8");
                return null;
            }
        }

        @Override
        protected Response<String> parseNetworkResponse(NetworkResponse response) {
            String responseString = "";
            if (response != null) {
                responseString = String.valueOf(response.statusCode);
                // can get more details such as response.headers
            }
            return Response.success(responseString, HttpHeaderParser.parseCacheHeaders(response));
        }
    };

    requestQueue.add(stringRequest);
} catch (JSONException e) {
    e.printStackTrace();
}

Answer 2

我喜欢this一个，但问题中请求的是sending JSON not string，在此处重新发布代码，以防原始github被删除或更改，并且这个被发现对某人有用

public static void postNewComment(Context context,final UserAccount userAccount,final String comment,final int blogId,final int postId){
    mPostCommentResponse.requestStarted();
    RequestQueue queue = Volley.newRequestQueue(context);
    StringRequest sr = new StringRequest(Request.Method.POST,"http://api.someservice.com/post/comment", new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {
            mPostCommentResponse.requestCompleted();
        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            mPostCommentResponse.requestEndedWithError(error);
        }
    }){
        @Override
        protected Map<String,String> getParams(){
            Map<String,String> params = new HashMap<String, String>();
            params.put("user",userAccount.getUsername());
            params.put("pass",userAccount.getPassword());
            params.put("comment", Uri.encode(comment));
            params.put("comment_post_ID",String.valueOf(postId));
            params.put("blogId",String.valueOf(blogId));

            return params;
        }

        @Override
        public Map<String, String> getHeaders() throws AuthFailureError {
            Map<String,String> params = new HashMap<String, String>();
            params.put("Content-Type","application/x-www-form-urlencoded");
            return params;
        }
    };
    queue.add(sr);
}

public interface PostCommentResponseListener {
    public void requestStarted();
    public void requestCompleted();
    public void requestEndedWithError(VolleyError error);
}

Answer 3

Name = editTextName.getText().toString().trim();
Email = editTextEmail.getText().toString().trim();
Phone = editTextMobile.getText().toString().trim();


JSONArray jsonArray = new JSONArray();
jsonArray.put(Name);
jsonArray.put(Email);
jsonArray.put(Phone);
final String mRequestBody = jsonArray.toString();

StringRequest stringRequest = new StringRequest(Request.Method.PUT, OTP_Url, new Response.Listener<String>() {
    @Override
    public void onResponse(String response) {
        Log.v("LOG_VOLLEY", response);

    }
}, new Response.ErrorListener() {
    @Override
    public void onErrorResponse(VolleyError error) {
        Log.e("LOG_VOLLEY", error.toString());
    }
}) {
    @Override
    public String getBodyContentType() {
        return "application/json; charset=utf-8";
    }

    @Override
    public byte[] getBody() throws AuthFailureError {
        try {
            return mRequestBody == null ? null : mRequestBody.getBytes("utf-8");
        } catch (UnsupportedEncodingException uee) {
            VolleyLog.wtf("Unsupported Encoding while trying to get the bytes of %s using %s", mRequestBody, "utf-8");
            return null;
        }
    }

};
stringRequest.setShouldCache(false);
VollySupport.getmInstance(RegisterActivity.this).addToRequestque(stringRequest);

Answer 4

我制作了一个调用vollyrequest的函数。您只需要传递参数

public void callvolly(final String username, final String password){
    RequestQueue MyRequestQueue = Volley.newRequestQueue(this);
    String url = "http://your_url.com/abc.php"; // <----enter your post url here
    StringRequest MyStringRequest = new StringRequest(Request.Method.POST, url, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {
            //This code is executed if the server responds, whether or not the response contains data.
            //The String 'response' contains the server's response.
        }
    }, new Response.ErrorListener() { //Create an error listener to handle errors appropriately.
        @Override
        public void onErrorResponse(VolleyError error) {
            //This code is executed if there is an error.
        }
    }) {
        protected Map<String, String> getParams() {
            Map<String, String> MyData = new HashMap<String, String>();
            MyData.put("username", username);             
            MyData.put("password", password);                
            return MyData;
        }
    };


    MyRequestQueue.add(MyStringRequest);
}

Answer 5

StringRequest stringRequest = new StringRequest(Request.Method.POST, URL, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {
            Log.e("Rest response",response);
        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            Log.e("Rest response",error.toString());
        }
    }){
        @Override
        protected Map<String,String> getParams(){
            Map<String,String> params = new HashMap<String,String>();
            params.put("name","xyz");
            return params;
        }

        @Override
        public Map<String,String> getHeaders() throws AuthFailureError {
            Map<String,String> params = new HashMap<String,String>();
            params.put("content-type","application/fesf");
            return params;
        }

    };

    requestQueue.add(stringRequest);

如何使用带有字体的凌空发送POST请求？

5 个答案: