我试图在Highcharts中根据mx+b
(斜率+ y轴截距)公式绘制线性回归线,使用regression-js生成回归公式。
我遇到的问题是,Highcharts似乎想要[[x1, y1], [x2, y2]]
格式的回归线,但我不能从斜率和y截距得到一个开始和结束。< / p>
所以:
是否可以在斜坡上绘制一条Highcharts线?或者是否有一个JS回归库,它将根据我下面的数据数组输出[[x1, y1], [x2, y2]]
格式化的行?
我现在正在做的事情:
data = [[11.6,14.7],[12.2,15.9],[10.7,14.8],[14,11.7],[12.5,13.2],[10,11.3],[10.1,11],[13.5,19.1]];
slope = regression('linear', data); // result: slope.equation = [slope, y-intercept]
$('#scatter').highcharts({
chart: {
type: 'scatter',
zoomType: 'xy'
},
plotOptions: {
scatter: {
marker: {
radius: 5,
states: {
hover: {
enabled: true,
lineColor: 'rgb(100,100,100)'
}
}
},
states: {
hover: {
marker: {
enabled: false
}
}
},
tooltip: {
headerFormat: '<b>{series.name}</b><br>',
pointFormat: '{point.x} cm, {point.y} kg'
}
}
},
series: [
{
type: 'line',
name: 'Regression Line',
data: [[0, 0], [5, 4.51]], // You see the problem here: I've got mx + b and this wants x1 y1 x2 y2
marker: {
enabled: false
},
states: {
hover: {
lineWidth: 0
}
},
enableMouseTracking: false
},
{
name: 'Water Temperature vs. Air Temperature',
color: 'rgba(119, 152, 191, .5)',
data: data
}]
});
答案 0 :(得分:2)
整洁的问题。以下是我的表现方式:
var data = [[11.6,14.7],[12.2,15.9],[10.7,14.8],[14,11.7],[12.5,13.2],[10,11.3],[10.1,11],[13.5,19.1]];
var ymxb = regression('linear', data);
// get the slope and x intercept from the equation
var m = ymxb.equation[0], b = ymxb.equation[1];
// create array of x values
var xs = [];
data.forEach(function(d){
xs.push(d[0]);
});
// get the max and min values of x, and calculate
// the corresponding y value using that x, m, and b
var x0 = Math.min.apply(null, xs),
y0 = m*x0 + b;
var xf = Math.max.apply(null, xs),
yf = m*xf + b;
...
// that gives you your two coordinates
series: [
{
type: 'line',
name: 'Regression Line',
data: [[x0, y0], [xf, yf]],
...
结果:
答案 1 :(得分:1)
您还可以使用我们存储空间中提供的扩展程序。
http://www.highcharts.com/plugin-registry/single/22/Highcharts%20regression