Question

可以任何人告诉我如何解析以下

    <string xmlns="http://tempuri.org/">
[{"OSID":"2","PhoneVersion":"IPHONE5","PhoneOS":"IOS","ImageName":"t_3@2x.png","ImageID":"3"},{"OSID":"2","PhoneVersion":"IPHONE5","PhoneOS":"IOS","ImageName":"t_4@2x.png","ImageID":"4"},{"OSID":"2","PhoneVersion":"IPHONE5","PhoneOS":"IOS","ImageName":"t_5@2x.png","ImageID":"5"},{"OSID":"2","PhoneVersion":"IPHONE5","PhoneOS":"IOS","ImageName":"t_6@2x.png","ImageID":"6"},{"OSID":"2","PhoneVersion":"IPHONE5","PhoneOS":"IOS","ImageName":"t_7@2x.png","ImageID":"7"},{"OSID":"2","PhoneVersion":"IPHONE5","PhoneOS":"IOS","ImageName":"t_8@2x.png","ImageID":"8"},{"OSID":"2","PhoneVersion":"IPHONE5","PhoneOS":"IOS","ImageName":"t_9@2x.png","ImageID":"9"},{"OSID":"2","PhoneVersion":"IPHONE5","PhoneOS":"IOS","ImageName":"t_10@2x.png","ImageID":"10"},{"OSID":"2","PhoneVersion":"IPHONE5","PhoneOS":"IOS","ImageName":"t_11@2x.png","ImageID":"11"},{"OSID":"2","PhoneVersion":"IPHONE5","PhoneOS":"IOS","ImageName":"t_12@2x.png","ImageID":"12"}]
</string>

我在下面的方法的帮助下用一些参赛者打我的网址，是不是？

 public String getJSON(String url, int timeout) {
                HttpURLConnection c = null;
                try {
                    URL u = new URL(url);
                    c = (HttpURLConnection) u.openConnection();
                    c.setRequestMethod("GET");
                    c.setRequestProperty("Content-length", "0");
                    c.setUseCaches(false);
                    c.setAllowUserInteraction(false);
                    c.setConnectTimeout(timeout);
                    c.setReadTimeout(timeout);
                    c.setRequestProperty("Content-Type", "application/json");
                    c.connect();
                    int status = c.getResponseCode();

                    switch (status) {
                        case 200:
                        case 201:
                            BufferedReader br = new BufferedReader(new InputStreamReader(c.getInputStream()));
                            StringBuilder sb = new StringBuilder();
                            String line;
                            while ((line = br.readLine()) != null) {
                                sb.append(line+"\n");
                            }
                            br.close();
                            return sb.toString();
                    }

                } catch (MalformedURLException ex) {
                    Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
                } catch (IOException ex) {
                    Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
                } finally {
                    if (c != null) {
                        try {
                            c.disconnect();
                        } catch (Exception ex) {
                            Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
                        }
                    }
                }
                return null;
            }

是正确的做法和如何解析回复请用源代码回答我。

Answer 1

感谢大家的回复，让我明白我需要采取哪些步骤。好吧，我在询问如何在解析xml时删除xml标签很明显，与json相比，解析xml更加棘手，而且从教程中我是学习如何解析它但是如何解析这个xml响应是有问题的没有名称空间，没有方法名称等

所以如果在同一个案例中有一个陷阱（特别是当网页设计师/服务器端程序员把它放在你身上时，我会发布这个答案:(。）

我使用了下面的类来解析没有名称空间的xml，并且r返回了我的字符串。代码如下所示

public class StringXmlParser {
// your xml doesn't have any name spacing so make it null.
private static final String ns = null;

public String parse(InputStream in) throws XmlPullParserException, IOException {
    try {
        XmlPullParser parser = Xml.newPullParser();
        parser.setFeature(XmlPullParser.FEATURE_PROCESS_NAMESPACES, false);
        parser.setInput(in,null);
        parser.nextTag();
        return readString(parser);
    } finally {
        in.close();
    }
}

private String readString(XmlPullParser parser) throws XmlPullParserException, IOException {
    parser.require(XmlPullParser.START_TAG, ns, "string");
    String jsonString = readText(parser);
    parser.require(XmlPullParser.END_TAG, ns, "string");
    return jsonString;
}

private String readText(XmlPullParser parser) throws IOException, XmlPullParserException {
    String result = "";
    if (parser.next() == XmlPullParser.TEXT) {
        result = parser.getText();
        parser.nextTag();
    }
    return result;
}

}

这解决了我的情况。我希望如果有人想要相同的解决方案，那么它可能会帮助他。只需上传答案，其唯一目的就是帮助纯粹的初学者。

如何解析xml包装json

1 个答案: