Question

我在RestSharp RestRequest.Content对象中有以下XML。如何在C＃中遍历它或更改为JSON以获取FULLNAME节点？

<ns1:MT_Get_Name_Res xmlns:ns1="http://hse.pd.com">
    <fullname>Gandalf Elizabeth Cfieulle02</fullname>
    <error>Success</error>
</ns1:MT_Get_Name_Res>

我已经尝试过的事情：

JSON - 返回一个搞砸的JSON对象，然后无法解析到我的本地对象

XmlDocument doc = new XmlDocument();
doc.LoadXml(response.Content);
string json = Newtonsoft.Json.JsonConvert.SerializeXmlNode(doc);
EmployeeSAPObject emp = JsonConvert.DeserializeObject<EmployeeSAPObject>(json);

C＃XML解析 - fullname为null：

XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(response.Content); // suppose that myXmlString contains "<Names>...</Names>"

XmlNodeList xnList = xmlDoc.SelectNodes("/MT_Get_Name_Res/fullname");
foreach (XmlNode xn in xnList)
{
    string fullName = xn["fullname"].InnerText;
}

这是我的EmployeeSAPObject类

public class EmployeeSAPObject
{
    public string fullname { get; set; }
    public string error { get; set; }
}

Answer 1

您需要添加命名空间，并且希望使用XDocument而不是XmlDocument：

void Main()
{
    var data = @"<ns1:MT_Get_Name_Res xmlns:ns1=""http://hse.pd.com"">
    <fullname>Gandalf Elizabeth Cfieulle02</fullname>
    <error>Success</error>
</ns1:MT_Get_Name_Res>";

    var xdoc = XDocument.Parse(data);
    Console.WriteLine(xdoc.ToString());

    XNamespace ns = "http://hse.pd.com";
    var result = xdoc.Element(ns + "MT_Get_Name_Res").Element("fullname").Value;
    Console.WriteLine(result);

    Console.ReadLine();
}

Answer 2

用适当的属性装饰你的EmployeeSAPObject并反序列化它：

[XmlRoot("MT_Get_Name_Res", Namespace = "http://hse.pd.com")]
public class EmployeeSAPObject
{
    [XmlElement(Namespace="")]
    public string fullname { get; set; }
    [XmlElement(Namespace = "")]
    public string error { get; set; }
}

然后使用它：

        EmployeeSAPObject employee;
        using (StringReader reader = new StringReader(response.Content))
            employee = (EmployeeSAPObject)(new XmlSerializer(typeof(EmployeeSAPObject))).Deserialize(reader);

        Debug.Assert(employee.fullname == "Gandalf Elizabeth Cfieulle02"); // No assert

如何解析这个特定的XML来获取C＃中的FULLNAME节点？

2 个答案: