如何订购矩阵？

Question

我是否会根据计算的两个矩阵对带有括号的矩阵进行排序，例如（A1）（A2（A3A4））

import sys
s=[[]]
from pprint import pprint
def order(i,j):
    if(i==j):
        print("A" + str(i))
    else:
        k = s[i][j]
        print("(")
        order(i,k)
        order(k+1,j)
        print(")")


def minmult(p, n,par):
    m = [[0 for x in range(n)] for x in range(n)]
    s = [[0 for x in range(n)] for x in range(n)]

for i in range(1, n):
    m[i][i] = 0
    s[i][i] = 0


for L in range(2, n):
    for i in range(1, n-L+1):
        j = i+L-1
        m[i][j] = sys.maxsize
        for k in range(i, j):
            q = m[i][k] + m[k+1][j] + p[i-1]*p[k]*p[j]
            if q < m[i][j]:
                m[i][j] = q
                s[i][j]=k
            print(str(order(i,j)))
pprint(m)
pprint(s)
return m[1][n-1]


array=[10,4,5,20,2,50]
size = len(array)
print(str(minmult(array,size,0)))

不知道如何使方法顺序有效，任何帮助都会很棒。