Question

我想在我的UITableView中加入一个滑动功能，我想从那里执行一个segue。例如，当向左滑动单元格时，它会显示Edit按钮，当按下此编辑按钮时，它会打开一个新的ViewController.UI

Answer 1

请尝试以下代码：

let cSelector : Selector = “swipeAction”

let rightSwipe = UISwipeGestureRecognizer(target: self, action: cSelector)
rightSwipe.direction = UISwipeGestureRecognizerDirection.Right
mainTableView.addGestureRecognizer(rightSwipe) // Or you can add it to cell

并创建滑动操作：

func swipeAction()
{
    // TODO 
    self.performSegueWithIdentifier("segueId", sender: nil)
}

或者你可以在滑动单元格时直接调用segue（如果你实现了内嵌滑动，如canEditCellForRow）

并实施prepareForSegue方法

// MARK: - Navigation

// In a storyboard-based application, you will often want to do a little preparation before navigation

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {

    // Get the new view controller using segue.destinationViewController.
    // Pass the selected object to the new view controller.

    let controller = segue.destinationViewController as YourDestViewController
    controller.someData = // Pass some object if you need
}

Answer 2

要在代码中预先形成segue，您可以使用代码行：self.preformSegueWithIdentifyer("idenyidfyer",nil。要在视图视图控制器中创建segue，请控制从视图控制器单击并拖动到所需的视图控制器。单击segue并将标识符更改为您想要的内容。

如何从UITableView滑动触发segue到swift中的Edit

2 个答案: