我有两个uitableviewcontroller,一个是列表表,另一个是编辑表。 我使用附件动作来编辑项目。效果很好。
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "EditItem" {
let controller = segue.destination as! ItemDetailViewController
controller.delegate = self
if let indexPath = tableView.indexPath(for: sender as! UITableViewCell) {
controller.itemToEdit = items[indexPath.row]
}
}
}
现在我添加了滑动功能来编辑项目
override func tableView(_ tableView: UITableView, trailingSwipeActionsConfigurationForRowAt indexPath: IndexPath) -> UISwipeActionsConfiguration? {
let edit = UIContextualAction(style: .normal, title: "Edit") { action, view, completion in
self.performSegue(withIdentifier: "EditItem", sender: self)
completion(true)
}
let delete = UIContextualAction(style: .destructive, title: "Delete") { [weak self] action, view, completion in
self?.items.remove(at: indexPath.row)
tableView.deleteRows(at: [indexPath], with: UITableView.RowAnimation.automatic)
self?.saveChannelListItems()
completion(true)
}
edit.backgroundColor = .purple
edit.image = #imageLiteral(resourceName: "edit")
delete.backgroundColor = .red
delete.image = #imageLiteral(resourceName: "delete")
return UISwipeActionsConfiguration(actions: [delete, edit])
}
那我有错误。
无法将类型'abc.ListController'(0x1089b1398)的值强制转换为'UITableViewCell'(0x1150f18e0)。
如何滑动以编辑项目?
答案 0 :(得分:0)
您在此处发送self
参数中的vc的sender
self.performSegue(withIdentifier: "EditItem", sender: self)
并强行将其解包到单元中
if let indexPath = tableView.indexPath(for: sender as! UITableViewCell) {
相反,您可以这样做
self.performSegue(withIdentifier: "EditItem", sender:items[indexPath.row])
使用
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "EditItem" {
let controller = segue.destination as! ItemDetailViewController
controller.delegate = self
controller.itemToEdit = sender as! ItemType // where ItemType is the type of the array elements
}
}
}