Question

我新学习shell脚本！我尝试了下面的代码，但我有错误

第15行：意外标记`elif
附近的语法错误

#!/bin/bash

read -p "Enter the number : " n

if [ $n -eq 1 ]
then
    echo "$n is equal to 1 true"

    elif [ $n -lt 4 ]
    then
        echo "$n is less than value of 4 ture"
    else
        echo "$n is not less then value of 4 false"

    elif [ $n -gt 10 ]
    then
        echo "$n is greater than the value of 10 true"
    else
        echo "$n is not greater than the value of 10 false"

    if [ $n -ge 0 ]
    then
        echo "$n is greater than or equal to 0"
    else
        echo "$n is not greater than or equal to 0"
    fi
else
    "Bye"
fi

有人可以帮忙吗？

Answer 1

要说出你的意图有点难。正确的答案取决于你想在这里做什么。我的猜测是你想要这个：

if [ $n -eq 1 ]
then
    echo "$n is equal to 1 true"

elif [ $n -lt 4 ]
then
    echo "$n is less than value of 4 true"

elif [ $n -gt 10 ]
then
    echo "$n is greater than the value of 10 true"

elif [ $n -ge 0 ]
then
    # This will be true if $n is >= 4 and <= 10 
    echo "$n is greater than or equal to 0"
else
    # Negative
    "Bye"
fi

在一个地方unix all if语句

1 个答案: