Question

这是我的剧本：

echo "Name"

read name

if [ "$name" == "abcd" ]; then

 echo "Password"

 read password

 if [ "$password == "pwd" ]; then

  echo "Hello"

 else

  echo "Wrong password"

 fi

else

 echo "wrong username"

fi

这是我运行时得到的输出：

sh hello.sh

Name

abcd

hello.sh: line 14: unexpected EOF while looking for matching `"'

hello.sh: line 16: syntax error: unexpected end of file

这里有什么想法吗？这可能是一个非常愚蠢的，但我浪费了将近一个小时。

Answer 1

if [ "$password == "pwd" ]; then

"

之前有$password个匹配

Answer 2

您可以使用case。这是一个例子。出于安全原因，您不希望告诉任何人哪个组件出错。

echo "Name"
read name
echo "Password"
read password
case "${name}${password}" in
 "abcdpwd" ) 
     echo "hello";;
  *) echo "User or password is wrong";;
esac

Answer 3

在Shell脚本中。

nameof()

Answer 4

if [ "$name" == "abcd" ];
then
  echo "Password"
  read password
  if [ "$password" == "pwd" ];
  then
    echo "Hello"
  else
    echo "Wrong password"
  fi
else
  echo "wrong username"
fi

Shell脚本中的Nested-If语句

4 个答案: