如何使用PHP返回在字符串中找到的特殊字符

Question

我想使用PHP代码获取字符串中的特殊字符，这是我的试用代码：

 $page_num =">256";
 if(preg_match('^[-<>]+$', $page_num))   
 {
        //Here it should returns special chars present in string..
 }

Answer 1

检查这个

$page_num =">256";
 if(preg_match_all('/\W/', $page_num,$matches))
 {
       print_r($matches);
 }

Answer 2

您错过的是 ending delimiter

$page_num =">256";
 if(preg_match('^[-<>]+$^', $page_num))   
                        ^// this one
 {
    //Here it should returns special chars present in string..
 } 

演示代码here

或者你可以试试这个，

$string = 'your string here';

if (preg_match('/[\'^£$%&*()}{@#~?><>,|=_+¬-]/', $string))
{
    echo "yes";
} else {
    echo "no";
}

还有一个解决方案是

preg_match('![^a-z0-9]!i', $string);