Question

String s = "select from(select * LEAF_CATEG_ID,a.FROM_EMAIL_ADDRESS,a.HARD_BOUNCE_TYPE";
    Pattern p=Pattern.compile("[^a-zA-Z0-9]",Pattern.CASE_INSENSITIVE);
    String[] parts=p.split(s);

    for(int i=0;i<parts.length;i++){
        System.out.println("After finding special characters i am able to split the characters:"+parts[i]);

    }

我的期望输出是：

After finding special characters i am able to split the characters:select
After finding special characters i am able to split the characters:from
After finding special characters i am able to split the characters:(
After finding special characters i am able to split the characters:select
After finding special characters i am able to split the characters:*
After finding special characters i am able to split the characters:
After finding special characters i am able to split the characters:LEAF
After finding special characters i am able to split the characters:_
After finding special characters i am able to split the characters:CATEG
After finding special characters i am able to split the characters:_
After finding special characters i am able to split the characters:ID
After finding special characters i am able to split the characters:,
After finding special characters i am able to split the characters:a
After finding special characters i am able to split the characters:.
After finding special characters i am able to split the characters:FROM

但我得到的是：

After finding special characters i am able to split the characters:select
After finding special characters i am able to split the characters:from
After finding special characters i am able to split the characters:select
After finding special characters i am able to split the characters:
After finding special characters i am able to split the characters:
After finding special characters i am able to split the characters:LEAF
After finding special characters i am able to split the characters:CATEG
After finding special characters i am able to split the characters:ID
After finding special characters i am able to split the characters:a
After finding special characters i am able to split the characters:FROM

我想将上面的字符串拆分为包含特殊字符的对象的String数组但是我当前的代码不包含特殊字符，它跳过特殊字符请帮助我，提前致谢....

Answer 1

要在Java中拆分和保留分隔符，您需要使用 lookarounds ：前瞻和后视的组合，以及您选择的分隔符。

您的案例中的分隔符是除ASCII字母或数字以外的任何字符。它可以通过

来实现

Pattern p=Pattern.compile("(?<=[^a-z0-9])|(?=[^a-z0-9])",Pattern.CASE_INSENSITIVE);

请注意，在使用[A-Z]标记时，您不需要CASE_INSENSITIVE。

请参阅IDEONE demo，此处为the regex demo。

正则表达式匹配两个

的空位置

(?<=[^a-z0-9]) - 前面加上a-z，A-Z或0-9
(?=[^a-z0-9]) - 后跟a-z，A-Z或0-9以外的字符。

如何在字符串数组中包含特殊字符。同时使用Regex Pattern的特殊字符拆分字符串

1 个答案: