Question

我注意到它是一种流行的TypeError，但我找不到解决方案。看看我的代码并说出错了，请：

import random
players_list = []

def add_player():
    possible_flags = {'is_computer', 'is_human'}
    decision = -1
    while decision != '0':
        player_name = input('Give a name: ')

        while player_flag not in possible_flags
            player_flag = input("Type 'is_computer' or 'is_human': ") #is_computer or is_human

        players_list.append({'player_name': player_name, 'player_flag': player_flag, 'player_decision': None})

        decision = input('Do you want add a new player [1]? To leave type [1] ')


def play():
    options = {1: 'rock', 2: 'paper', 3: 'scissors', 4: 'lizard', 5: 'Spock'}
    for i in players_list:
        if('is_computer' in players_list[i]):
            player_decision = random.choice(options)
        elif('is_player' in players_list[i]):
            player_decision = input()

        player_list[i]['player_decision'] = options[player_decision]


add_player()
play()

问题在于：

if('is_computer' in players_list[i]):

我也试过了：

if('is_computer' in players_list[i]['player_flag']):

但这也行不通。我只是不明白。我把dict放在列表中是否犯了错误？我会很感激任何关于它的文章的链接。

非常感谢

Answer 1

for i in players_list

i不是索引，而是元素本身。您可能希望将代码段重写为：

for player in player_list:
    if player['player_flag'] == 'is_computer':
        ...

列表中的Dict和TypeError：list索引必须是整数，而不是dict

1 个答案: