def take_turn(Nplayers, hands, player, pile, turn):
while finished(hands) is not True:
pile.append(hands[player][0]) # this line
hands[player].pop(0)
while pile[-1] <= 10:
print(turn, ':', '\nPile:', pile, '\nHands\n', '\n'.join(map(str, hands)), '\n')
check_players(Nplayers, hands, player, pile, turn)
turn += 1
player = (player + 1) % Nplayers
if len(hands[player]) == 0:
hands.pop(player)
Nplayers -= 1
player = player % Nplayers
pile.append(hands[player][0])
hands[player].pop(0)
if table[-1] > 10:
break
penalty_card(Nplayers, hands, player, pile, turn)
return turn
标记为(#this line)的行返回标题中所述的错误,在我的程序中我将玩家设置为最初等于0,所以应该没有问题吗?
编辑:hands是一个列表列表,player是一个整数
答案 0 :(得分:0)
如果提供了工作代码示例,那么帮助会更容易。看起来有许多副作用的功能。也许你可以包括一些最小的模拟和一个如下所示的样本调用,以便对问题进行包含,可运行的演示?
def finished(hands):
if len(hands) == 0:
return True
return False
def check_players(*args, **kwargs):
pass
def penalty_card(*args, **kwargs):
pass
table = [9]
def take_turn(Nplayers, hands, player, pile, turn):
while finished(hands) is not True:
pile.append(hands[player][0]) # this line
hands[player].pop(0)
while pile[-1] <= 10:
print(turn, ':', '\nPile:', pile, '\nHands\n', '\n'.join(map(str, hands)), '\n')
check_players(Nplayers, hands, player, pile, turn)
turn += 1
player = (player + 1) % Nplayers
if len(hands[player]) == 0:
hands.pop(player)
Nplayers -= 1
player = player % Nplayers
pile.append(hands[player][0])
hands[player].pop(0)
if table[-1] > 10:
break
penalty_card(Nplayers, hands, player, pile, turn)
return turn
take_turn(Nplayers=1, hands=[[1,1,1], [1,1], [1]], player=0, pile=[5, 5], turn=3)