Question

我在index.html页面中有这段代码

<html>
<head>
<title>Login</title>
</head>
<body>
<h2>Admin Panel</h2>

<FORM NAME ="form1" METHOD ="POST" ACTION = "login.php">

<INPUT TYPE = "TEXT" name="username">
<INPUT TYPE = "PASSWORD" name="password">
<INPUT TYPE = "Submit" NAME = "Submit1" VALUE = "Login">

</FORM>

</body>
</html>

和我的login.php文件中的代码

<html>
<head> 
<title>Login</title> 
</head>
<body>

<?php 

$adminUsername = "dushyant30suthar";

$adminPassword = "12345";

$enteredUsername = $_POST['username'];

$enteredPassword = $_POST['password'];
print ($enteredPassword);

if($enteredUsername == $adminUsername && $enteredPassword == $adminPassword)
  {
   print("Logged in");
   print ($username);
  }
else
  {
  print("Login Failed");
  print ($enteredUsername);
  print ($enteredPassword);
  print ($adminUsername);
  print ($adminPassword);
   }


 ?>
</body>
</html>

当我尝试打印我从index.html获得的值时，它没有显示任何数据，但是我在login.php中修复的值正在显示。

Answer 1

您的登录代码可以通过我正在测试的内容正常运行，但您仍然会在login.php中出错：

if($enteredUsername == $adminUsername && $enteredPassword == $adminPassword)
  {
   print("Logged in");
   print ($username);
  }

在您向我们展示$username的代码中，您可能希望将其更改为：

if($enteredUsername == $adminUsername && $enteredPassword == $adminPassword)
  {
   print("Logged in");
   print ($enteredUsername);
  }

Answer 2

以下是index.html的代码：

if (foo == nullptr)

将此代码用于<!DOCTYPE html> <html> <head> <title>Login</title> </head> <body> <h2>Admin Panel</h2> <form name="form1" method="post" action="login.php"> <input type="text" name="username"> <input type="password" name="password"> <input type="submit" name="submit1" value="login"> </form> </body> </html>文件，它正在运行：

login.php

我已经添加了一张支票，如果已经提交了必要的表格：

<!DOCTYPE html>
<html>
<head> 
<title>Login</title> 
</head>
<body>
<?php
$adminUsername = "dushyant30suthar";

$adminPassword = "12345";


if (isset($_POST['submit1'])) {
  $enteredUsername = $_POST['username'];

  $enteredPassword = $_POST['password'];

  print ($enteredPassword);

  if($enteredUsername == $adminUsername && $enteredPassword == $adminPassword)
    {
     print("Logged in");
     print ($enteredUsername);
    }
  else
    {
    print("Login Failed");
    print ($enteredUsername);
    print ($enteredPassword);
    print ($adminUsername);
    print ($adminPassword);
     }
}


 ?>
</body>
</html>

已修复：if (isset($_POST['submit1'])) {未定义，我使用$username更改了它。

无法将数据从html表单获取到php脚本

2 个答案: