我想使用printf在整齐的列中打印东西。
happening 0.083333 [4]
hi 0.083333 [0]
if 0.083333 [8]
important 0.083333 [7]
is 0.250000 [3, 5, 10]
it 0.166667 [6, 9]
tagged 0.083333 [11]
there 0.083333 [1]
what 0.083333 [2]
我有这段代码System.out.printf("%s %.6f %s \n", word, web.getFrequency(word), loc);
,但它打印出来:
happening 0.083333 [ 4 ]
hi 0.083333 [ 0 ]
if 0.083333 [ 8 ]
important 0.083333 [ 7 ]
is 0.250000 [ 3 5 10 ]
it 0.166667 [ 6 9 ]
tagged 0.083333 [ 11 ]
there 0.083333 [ 1 ]
what 0.083333 [ 2 ]
任何帮助都将不胜感激。
答案 0 :(得分:3)
我会用这个:
System.out.printf ("%-30s %1.7f %s%n", word, etc, etc2);
答案 1 :(得分:1)
您可以获取所有单词字符串的最大长度,并将该长度存储在变量max
中。使用for循环获取max
,然后创建一个String
,其格式为连接普通printf格式和max变量以用作宽度。此外,\t
会放入制表符。
int max = 0;
for (int ii = 0; ii < numberOfStrings; ii++)
{
max = (word.length() > max) ? word.length() : max;
}
String format = "%" + max + "s\t%.6f\t%s \n";
System.out.printf(format, word, web.getFrequency(word), loc);
答案 2 :(得分:1)
System.out.format("%-8s%-8s%-8s\n","a","b","pow(b,a)");
System.out.format("%-8d%-8d%-8d\n",1,2,1);
System.out.format("%-8d%-8d%-8d\n",2,3,8);
System.out.format("%-8d%-8d%-8d\n",3,4,81);
System.out.format("%-8d%-8d%-8d\n",4,5,1024);
System.out.format("%-8d%-8d%-8d\n",5,6,15625);
//the negative integer kinda sets it back to the number of space needed
答案 3 :(得分:0)
输入:
happening 0.083333 [4]
hi 0.083333 [0]
if 0.083333 [8]
important 0.083333 [7]
is 0.250000 [3, 5, 10]
it 0.166667 [6, 9]
tagged 0.083333 [11]
there 0.083333 [1]
what 0.083333 [2]
代码:
import java.util.Scanner;
public class MyClass {
private static final Scanner sc = new Scanner(System.in);
public static void main(String args[]) {
for(int i = 0 ; i < 9; i++){
String str = sc.next();
float f = sc.nextFloat();
String str2 = sc.nextLine();
System.out.printf("%-10s %f %s\n", str, f, str2);
}
sc.close();
}
}
输出:
happening 0.083333 [4]
hi 0.083333 [0]
if 0.083333 [8]
important 0.083333 [7]
is 0.250000 [3, 5, 10]
it 0.166667 [6, 9]
tagged 0.083333 [11]
there 0.083333 [1]
what 0.083333 [2]
使用-要使字符串左对齐,请使用字段宽度将其正确对齐。 在您的情况下,printf语句将为
System.out.printf("%-10s %.6f %s\n", word, web.getFrequency(word), loc);