Question

如何使printf正确输出printf代码中没有错误的方法。老师没有仔细阅读格式只是一个简单的例子。

public static void printReportHeadings(int [] employeeId, int [] dependents, double [] hours, double [] payRate )
{
    System.out.println("                             ABC PayRoll System ");
    System.out.println(" EmployeeId " + " Gross Pay " + " Federal Tax " + " State Tax " + " Net Pay ");

    for (int i = 0; i <7;i++)
    {
        float gross;
        double federal =0.0;
        double state = 0.0;
        double net = 0.0;

        gross = (float)(hours[i]*payRate[i]);
        federal = .2 * (gross-(dependents[i]*38.46));
        state = .032*gross; 
        net = gross - (federal+state);


        System.out.printf("%-15d %.01f % 15f%n", employeeId[i], gross, federal  , state, net) ;


    }

Answer 1

你有三个占位符和五个你试图绑定到这些占位符的东西。

观察：

 System.out.printf("%-15d %.01f % 15f%n", employeeId[i], gross, federal, state, net);

%-15d，%.01f和%15f都是整数的占位符，分别是两个浮点数。其他两个 - state和net - 根本就没有占位符。

为浮点类型添加几个占位符将解决您的问题：

System.out.printf("%-15d %.01f %15f %10f %10f%n", employeeId[i], gross, federal, state, net);

如何使这个printf打印方法没有格式错误

1 个答案: