Android FilePicker对话框仅适用于某些设备

时间:2015-11-01 13:21:59

标签: android filepicker aquery

我使用常规的样板代码在android上显示File Picker对话框。获得文件路径后,我使用aQuery将该文件上传到我的服务器。 但是,该代码仅适用于在Android 4.1.2上运行但不在任何其他设备上运行的旧三星手机。我使用许多设备对其进行了测试,但它仅适用于使用JellyBean的三星设备。

    Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
    intent.setType(minmeType);
    intent.addCategory(Intent.CATEGORY_OPENABLE);


    // special intent for Samsung file manager
    Intent sIntent = new Intent("com.sec.android.app.myfiles.PICK_DATA");
    // if you want any file type, you can skip next line
    sIntent.putExtra("CONTENT_TYPE", minmeType);
    sIntent.addCategory(Intent.CATEGORY_DEFAULT);

    Intent chooserIntent;
    if (getPackageManager().resolveActivity(sIntent, 0) != null) {
        // it is device with samsung file manager
       chooserIntent = Intent.createChooser(sIntent, "Open file");
       chooserIntent.putExtra(Intent.EXTRA_INITIAL_INTENTS, new Intent[]{intent});
    } else {
        chooserIntent = Intent.createChooser(intent, "Open file");
    }

    try {
        startActivityForResult(chooserIntent, PICKFILE_REQUEST_CODE);
    } catch (android.content.ActivityNotFoundException ex) {
        Toast.makeText(getApplicationContext(), "No suitable File Manager was found.\nPlease download a File Manager and try again.", Toast.LENGTH_LONG).show();
    }

onActivityResult代码是:

    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (data != null) {
        fPath = data.getDataString();
        File file = new File(fPath.substring(7));
        params.put("file" + noFilesAttached, file);
        noFilesAttached = noFilesAttached + 1;
        path.setText(noFilesAttached + " files attached ");
        upload.setText("Upload (" + noFilesAttached + ")");
        upload.setVisibility(View.VISIBLE);
        isUploaded = false;
    }
    super.onActivityResult(requestCode, resultCode, data);
}

我尝试将 fPath.substring(7)编辑为 fpath 但没有成功,我也不想使用任何第三方库。< / p>

提前致谢。

2 个答案:

答案 0 :(得分:0)

尝试使用此library

此库可能会修复您的要求。

答案 1 :(得分:0)

Data.getData()返回uri; 你需要一个文件路径; 尝试找到将uri转换为filepath的方法: 可能:

public static String getRealFilePath( final Context context, final Uri uri ) {  
    if ( null == uri ) return null;  
    final String scheme = uri.getScheme();  
    String data = null;  
    if ( scheme == null )  
        data = uri.getPath();  
    else if ( ContentResolver.SCHEME_FILE.equals( scheme ) ) {  
        data = uri.getPath();  
    } else if ( ContentResolver.SCHEME_CONTENT.equals( scheme ) ) {  
        Cursor cursor = context.getContentResolver().query( uri, new String[] { ImageColumns.DATA }, null, null, null );  
        if ( null != cursor ) {  
            if ( cursor.moveToFirst() ) {  
                int index = cursor.getColumnIndex( ImageColumns.DATA );  
                if ( index > -1 ) {  
                    data = cursor.getString( index );  
                }  
            }  
            cursor.close();  
        }  
    }  
    return data;  
}