考虑两个词典:
dict1 = {'a': 35, 'b': 39, 'c': 20} # (with the values as integers)
dict2 = {'a': 23, 'c': 12}
我想获得以下内容:
dict_new = {'a': 0.657, 'c': 0.6} # (with the values as floats, as values of dict2/dict1)
答案 0 :(得分:3)
您可以使用dict2.keys() & dict1
获取公共密钥,然后进行划分:
dict1 = {'a':35, 'b': 39, 'c':20} #(with the values as integers)
dict2 = {'a':23, 'c':12}
d3 = {k: dict2[k] / dict1[k] for k in dict2.keys() & dict1}
如果你希望四舍五入到三位小数的值使用round(dict2[k] / dict1[k],3)
,如果来自dict2的键应该总是在dict1中,那么你可以简单地迭代dict2的项目:
d = {k:v / dict1[k] for k,v in dict2.items()}
答案 1 :(得分:0)
dic_new = {}
for key in dic2.keys():
dic_new[key]=float(dict2[key])/dict1[key]