Question

我想播放框架将arraylist发送到我的Android应用程序。所以我可以在Android应用程序上查看列表。但是play框架无法返回ArrayList）我怎么解决这个问题？谢谢。

public static Result get_LatestList() throws ClassNotFoundException,
        SQLException {
    String latestList = "";
    ArrayList<String[]> etList = new ArrayList<String[]>(); 

    MultipartFormData body = request().body().asMultipartFormData();
    String pageNumber = body.asFormUrlEncoded().get("pageNumber")[0];
    Connection conn = null;
    Statement stmt = null;
    ResultSet rs = null;

    Class.forName("com.mysql.jdbc.Driver");
    conn = DriverManager.getConnection("jdbc:mysql://localhost/iea_db",
            "rt", "yt");
    stmt = conn.createStatement();
    rs = stmt.executeQuery("select * from List_Table;");
    while (rs.next()) {
        String[] oneSet = new String[4];

        oneSet[0] = rs.getString("userName");
        oneSet[1] = rs.getString("idName");
        oneSet[2] = rs.getString("comment");
        oneSet[3] = rs.getString("rank");
        etList.add(oneSet);
    }

    conn.close();                   
    return ok(etList);
}

Answer 1

我找到了一个解决方案：使用Json 在游戏框架中，执行以下操作：

    ObjectNode result = Json.newObject();

    result.put("draw", Integer.valueOf(params.get("draw")[0]));
    result.put("recordsTotal", iTotalRecords);
    result.put("recordsFilter", iTotalDisplayRecords);

    return ok(result);

在android中，执行此操作：

  @Override
    protected JSONObject doInBackground(String... _uri) {
        HttpClient httpClient = new DefaultHttpClient();
        HttpGet httpGet = new HttpGet(_uri[0]);
        try {
            HttpResponse httpResponse = httpClient.execute(httpGet);
            if (httpResponse.getStatusLine().getStatusCode() == HttpStatus.SC_OK) {
                ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
                httpResponse.getEntity().writeTo(outputStream);
                outputStream.close();
                return new JSONObject(outputStream.toString());
            } else {
                httpResponse.getEntity().getContent().close();
                throw new IOException();
            }
        } catch (IOException e) {
            e.printStackTrace();
        } catch (JSONException e) {
            e.printStackTrace();
        }
        return null;
    }

播放框架返回错误：找不到合适的ok方法（ArrayList <string []>）]

1 个答案: