Question

我正在编写一个计算空间和元音的程序而且它不起作用，我想我做了一个无限循环。我会告诉你我的代码：

int contar_p(char a[100]) {
    int i = 0, spaces = 1;

    while (a[i] != '\0' && i < 100) {
        if (a[i] == ' ') {
            spaces += 1;
            i++;
        }           

    }
    return spaces;
}

int contar_v(char b[100]) {
    int i = 0, counter = 0;

    while (b[i] != '\0' && i < 100) {
        if (b[i] == 'a' || b[i] == 'e' || b[i] == 'i' || b[i] == 'o' || b[i] == 'u') {
            counter += 1;
        }
        i++;
    }
    return counter;
}

int main(void){
    char phrase[100];
    int words = 0, vowels = 0;

    printf("write a phrase ");
    gets(phrase);

    palabras = contar_p(phrase);
    vocales = contar_v(phrase);

    printf("%d\n", words);
    printf("%d", vowels);

    return 0;
}

Answer 1

循环

i++

是一个无限循环。将if放在while (a[i]!='\0'){ // No need of condition i < 100 if(a[i]==' '){ spaces+=1; } i++; }之外。将其更改为

Person *aPerson = [[Person alloc] init];        

NSMutableArray *myArray = [[NSMutableArray alloc] init];        
[myArray addObject:@"First line"];        
[myArray addObject:@"Second line"];        
[myArray addObject:@"Third line"];        
[myArray addObject:@"Fourth line"];        
[myArray addObject:@"Fifth line"];

Answer 2

也许另一种方法可以帮助你更容易地理解事物，我的意思是你知道有A，E，I，O，U也不仅仅是a，e，i，o，u。你永远不应该使用get来代替使用fgets，无论如何看看下面的程序：

#include <stdlib.h>
#include <stdio.h>

void countVowels(char* array){
    int i,j,v;
    i=0;
    int count = 0;
    char vowel[]={'a','e','i','o','u','A','E','I','O','U'};

    while(array[i]!='\0'){
        for(v=0;v<10;v++){
            if (array[i]==vowel[v]){
                j=i;
                while(array[j]!='\0'){
                    array[j]=array[j+1];
                    j++;
                }
                count++;
                i--;
                break;
            }
        }
    i++;
  }

  printf("Found %d Vowels\n",count);
}

void contar_p(char a[100]) {
    int i = 0, spaces = 0;

    for(i=0;a[i]!='\0';i++){
        if(a[i]==' ')
        spaces++;
    }
    printf("Found %d Spaces\n",spaces);
}


int main(void){
    char a[]="aa bb EOU cc ii";
    countVowels(a);
    contar_p(a);
  return 0;
}

输出：

Found 7 Vowels
Found 4 Spaces

C计数空间中的无限循环

2 个答案: