mysql - 如何在SQL视图中计算年龄

我想要达到什么目标？

我正在尝试将客户详细信息生成到一个表中。客户名称和地址位于2个不同的表中，因此我创建了以下VIEW

SELECT dbo.Customer.CustomerId, dbo.Customer.GivenName + ' ' + dbo.Customer.FamilyName AS [CustomerName], dbo.Customer.DOB, dbo.Customer.Gender, 
                  dbo.Address.PostCode AS [Post Code], dbo.Address.Town AS Suburb, dbo.State.Code AS State

FROM    dbo.Address INNER JOIN
                  dbo.Cusotmer ON dbo.Address.AddressId = dbo.Customer.AddressID INNER JOIN
                  dbo.State ON dbo.Address.StateId = dbo.State.StateId

问题

如何在同一视图表中将DOB变为Age？

DOB是此格式中的日期列：2015-03-25

如何在SQL视图中计算年龄

0 个答案: