如何计算输入中使用它的年龄? 调用输入的代码是..
if(isset($keyage)){
$keyag = "AND bday_month LIKE '".$keyage."'";
}
但研究仅以月为基础,我如何看待年龄 - 谢谢
答案 0 :(得分:0)
尝试根据您的样本数据计算您的年龄:
select case when m_now>m_table then age
when m_now=m_table THEN
case when d_now=d_table then age ELSE
case when d_now<=d_table then age-1 else age end
end
ELSE age -1 END as age from
(select day(date(now()))d_now,day(date(CONCAT_WS('-',bday_year,bday_month,bday_day))) d_table,
month(date(now()))m_now, month(date(CONCAT_WS('-',bday_year,bday_month,bday_day)))m_table,
year(date(now()))-year(date(CONCAT_WS('-',bday_year,bday_month,bday_day))) age from
(Select 4 bday_month, 1 as bday_day , 1981 bday_year) as a) as a