Question

尝试帮助学生修理计算机数学课程的作业。当他运行他的小程序时，文本重叠。我们如何改变这个？

该作业旨在教授基本的if-then循环。

以下是代码：

import java.awt.*;
import java.lang.*;
import java.applet.*;
public class HibbertJ_if extends Applet {//more points lost
public void init() {   }
public void paint(Graphics g) {               
    int Rigby=(int)(Math.random()*123)+123;                      
    int Mario=(int)(Math.random()*321)+2;
    int SJF = (int)(Math.random()*2)+3;
    int Drake = (int)(Math.random()*9)+7;
    int Luigi = (int)(Math.random()*6)+8;
    int Benson = (int)(Math.random()*3)+4;
    boolean DoYouLikeToLose=getRandomBoolean();
    boolean DoYouLikeMario=getRandomBoolean();
    boolean DoYouSlackOff=getRandomBoolean();
    boolean IAmLolzingAtYou=getRandomBoolean();
    boolean IAmBeatingYou=getRandomBoolean();
    boolean DoYouLikeRegularShow=getRandomBoolean();
    String Go="Mr. Win";
    String Bball="Wii U";
    String Hib="PS4";
    String Son="3DS";
    String Marshall="Compaq";
    String Jordan="Beats";
    String student="sweeeeet";//need 3 string variables
    //type code here
    //start first word
    g.drawString("x = "+Rigby,100,15);
    g.drawString("y= "+SJF,200,15);
    g.drawString("Headaches= "+DoYouLikeMario,300,15);
    if(DoYouLikeMario)//equals NOT =, = assigns values, == says if same
    {
        if(SJF>=Rigby)//greater than or equal to
        {
            g.drawString("Mordo has a "+Rigby,10,15);

        }
        else
            g.drawString("SMB has a ",10,15);;
    }
    else
        g.drawString("SMG4 has a ",10,15);

    if(DoYouLikeMario)//equals NOT =, = assigns values, == says if same
    {
        g.drawString(Go,10,30);
        if(SJF>=Rigby)//greater than or equal to
            g.drawString(Bball,10,30);
    }
    if(Rigby<=SJF)//less than or equal to
        g.drawString(Hib,10,45);
    else if(SJF>Rigby)//greater than
        g.drawString(Son,10,60);
    else
    {
        g.drawString(student,10,75);
        if(Mario<SJF)//less than
        {
            g.drawString(Marshall,10,90);
            if(Rigby!=Rigby)//Not equal to
                g.drawString(student,10,105);
        }
    }
    if(Mario==SJF&&SJF>Rigby)//(equal to) AND (greater than)
        g.drawString(Jordan,10,120); 
      if(Luigi==Drake&&Benson>Rigby)//(equal to) AND (greater than)
        g.drawString(Bball,10,120); 
    if(Rigby==SJF||SJF==Mario)//(equal to) OR (equal to)
        g.drawString(student,10,135);
        if(Mario==Drake||Rigby==SJF)//(equal to) OR (equal to)
        g.drawString(Go,10,135);
    else
        g.drawString(Go,10,135);
    if(DoYouLikeMario)
        g.drawString(Bball,10,135);
    if(DoYouSlackOff)
        g.drawString(Hib,10,135);
    if(IAmLolzingAtYou)    
        g.drawString(Son,10,135);
    if(true)
        g.drawString("This always happens",1,100);
        //if(false); also works, ; means some line of code could be there
    }
   public boolean getRandomBoolean() {
       return Math.random() < 0.5;
   }
}

Answer 1

if(Rigby==SJF||SJF==Mario)
    g.drawString(student,10,135);
    if(Mario==Drake||Rigby==SJF)
    g.drawString(Go,10,135);
else
    g.drawString(Go,10,135);

没有花括号的块非常容易出错。在这种特定情况下，编译器将其解释为：

if(Rigby==SJF||SJF==Mario) {
    g.drawString(student,10,135);
}

if(Mario==Drake||Rigby==SJF) {
    g.drawString(Go,10,135);
} else {
    g.drawString(Go,10,135);
}

请注意它与缩进意味着什么有很大不同？最佳做法是在每个 if和else上添加花括号，即使它们是单行。这避免了许多未来的错误并且成本非常低。

除此之外，通过手动指定位置来绘制文本很难编写和维护。尝试使用layout manager，它们是专门创建的，以确保所有内容都在其位置且没有重叠

如何修复输出重叠

1 个答案: