在chrome中获得以下错误,看起来像path.line是我的json数据上的barfing我不知道为什么,它是有效的json。 感谢您提前提供任何帮助!
我的代码:数据和错误都在代码之后。谢谢!
<script>
// Set the dimensions of the canvas / graph
var margin = {top: 30, right: 20, bottom: 30, left: 50},
width = 600 - margin.left - margin.right,
height = 270 - margin.top - margin.bottom;
// Parse the date / time
var parseDate = d3.time.format("%d-%b-%y").parse;
// Set the ranges
var x = d3.time.scale().range([0, width]);
var y = d3.scale.linear().range([height, 0]);
// Define the axes
var xAxis = d3.svg.axis().scale(x)
.orient("bottom").ticks(5);
var yAxis = d3.svg.axis().scale(y)
.orient("left").ticks(5);
// Define the line
var valueline = d3.svg.line()
.x(function(d) { return x(d.date); })
.y(function(d) { return y(d.close); });
// Adds the svg canvas
var svg = d3.select("body")
.append("svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform",
"translate(" + margin.left + "," + margin.top + ")");
// Get the data
//d3.csv("data.csv", function(error, data) {
// data.forEach(function(d) {
// d.date = parseDate(d.date);
// d.close = +d.close;
// });
// Get the data
DateFormat inputFormat = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss.S");
d3.json("data.json", function(error, data) {
data.forEach(function(d) {
Date d.date = inputFormat.parse(d.SAMPLETIME);
// d.date = Date.parse(d.SAMPLETIME);
d.close = parseFloat(d.SAMPLEVALUE);
});
// Scale the range of the data
x.domain(d3.extent(data, function(d) { return d.date; }));
y.domain([0, d3.max(data, function(d) { return d.close; })]);
// Add the valueline path.
svg.append("path")
.attr("class", "line")
.attr("d", valueline(data));
// Add the X Axis
svg.append("g")
.attr("class", "x axis")
.attr("transform", "translate(0," + height + ")")
.call(xAxis);
// Add the Y Axis
svg.append("g")
.attr("class", "y axis")
.call(yAxis);
});
从js控制台获取的错误是(为简洁而缩短)
<path class="line" d="MNaN,210LNaN,210LNaN,210LNaN,210LNaN,210LNaN,210LNaN,210LNaN,210LNaN,210"></path>
我的json数据文件看起来像这样我正在使用SAMPLETIME和SAMPLEVALUE
[
{
"R_TABLE": "RN_QOS_DATA_0001",
"TABLE_ID": "7947",
"ROBOT": "xx",
"SOURCE": "xx.xx.xx.net",
"QOS": "QOS_PROC_QUEUE_LEN",
"SAMPLETIME": "18-OCT-15 06.13.28.000000 PM",
"SAMPLEVALUE": ".04"
},
{
"R_TABLE": "RN_QOS_DATA_0001",
"TABLE_ID": "7947",
"ROBOT": "xx",
"SOURCE": "xx.xx.xx.net",
"QOS": "QOS_PROC_QUEUE_LEN",
"SAMPLETIME": "18-OCT-15 06.23.28.000000 PM",
"SAMPLEVALUE": ".01"
},
{
"R_TABLE": "RN_QOS_DATA_0001",
"TABLE_ID": "7947",
"ROBOT": "xx",
"SOURCE": "xx.xx.xx.net",
"QOS": "QOS_PROC_QUEUE_LEN",
"SAMPLETIME": "18-OCT-15 06.33.28.000000 PM",
"SAMPLEVALUE": 0
}
]
答案 0 :(得分:1)
数据中的日期不是有效日期。
您可以在此fiddle
中看到这一点您可以先拆分此日期以删除时间,如下所示:
var date = '18-OCT-15 06.23.28.000000 PM'
//split the string by the space and take the first part
date.split(' ')[0];
// create new date object
var new_date = new Date(date)