我正在尝试将C＃代码转换为C
原始C＃代码
从下面的代码中调用Hex2Binary方法
import time
class Card(object):
""" A playing card. """
RANKS = ["A", "2", "3", "4", "5", "6", "7",
"8", "9", "10", "J", "Q", "K"]
SUITS = ["c", "d", "h", "s"]
def __init__(self, rank, suit):
self.rank = rank
self.suit = suit
def __str__(self):
rep = self.rank + self.suit
return rep
class Hand(object):
""" A hand of playing cards. """
def __init__(self):
self.cards = []
def __str__(self):
if self.cards:
rep = ""
for card in self.cards:
rep += str(card) + " "
else:
rep = "<empty>"
return rep
def clear(self):
self.cards = []
def add(self, card):
self.cards.append(card)
def give(self, card, other_hand):
self.cards.remove(card)
other_hand.add(card)
def passAgain(passAgain):
if passAgain == "y" or passAgain == "yes":
card1 = Card("A", "s")
card2 = Card("2", "s")
card3 = Card("3", "s")
card4 = Card("4", "s")
card5 = Card("5", "s")
firstHand = Hand()
secondHand = Hand()
thirdHand = Hand()
fourthHand = Hand()
lastHand = Hand()
firstHand.add(card1)
firstHand.add(card2)
firstHand.add(card3)
firstHand.add(card4)
firstHand.add(card5)
print ("First hand contains:",firstHand,)
firstHand.give(card1, secondHand)
print ("First hand gives first card to second hand and now has:", firstHand,)
print ("Second hand now has:", secondHand,)
firstHand.give(card2, secondHand)
print ("First hand gives second card to second hand and now has:", firstHand,)
print ("Second hand now has:", secondHand,)
firstHand.give(card3, secondHand)
print ("First hand gives third card to second hand and now has:", firstHand,)
print ("Second hand now has:", secondHand,)
firstHand.give(card4, secondHand)
print ("First hand gives fourth card to second hand and now has:", firstHand,)
print ("Second hand now has:", secondHand,)
firstHand.give(card5, secondHand)
print ("First hand gives last card to second hand and now has:", firstHand,)
print ("Second hand now has:", secondHand,)
print("\n")
time.sleep(2)
secondHand.give(card1, thirdHand)
print ("Second hand gives first card to third hand and now has:", secondHand,)
print ("Third hand now has:", thirdHand,)
secondHand.give(card2, thirdHand)
print ("Second hand gives second card to third hand and now has:", secondHand,)
print ("Third hand now has:", thirdHand,)
secondHand.give(card3, thirdHand)
print ("Second hand gives third card to third hand and now has:", secondHand,)
print ("Third hand now has:", thirdHand,)
secondHand.give(card4, thirdHand)
print ("Second hand gives fourth card to third hand and now has:", secondHand,)
print ("Third hand now has:", thirdHand,)
secondHand.give(card5, thirdHand)
print ("Second hand gives last card to third hand and now has:", secondHand,)
print ("Third hand now has:", thirdHand,)
print("\n")
time.sleep(2)
thirdHand.give(card1, fourthHand)
print ("Third hand gives first card to fourth hand and now has:", thirdHand,)
print ("Fourth hand now has:", fourthHand,)
thirdHand.give(card2, fourthHand)
print ("Third hand gives second card to fourth hand and now has:", thirdHand,)
print ("Fourth hand now has:", fourthHand,)
thirdHand.give(card3, fourthHand)
print ("Third hand gives third card to fourth hand and now has:", thirdHand,)
print ("Fourth hand now has:", fourthHand,)
thirdHand.give(card4, fourthHand)
print ("Third hand gives fourth card to fourth hand and now has:", thirdHand,)
print ("Fourth hand now has:", fourthHand,)
thirdHand.give(card5, fourthHand)
print ("Third hand gives last card to fourth hand and now has:", thirdHand,)
print ("Fourth hand now has:", fourthHand,)
print("\n")
time.sleep(2)
fourthHand.give(card1, lastHand)
print ("Fourth hand gives first card to last hand and now has:", fourthHand,)
print ("Last hand now has:", lastHand,)
fourthHand.give(card2, lastHand)
print ("Fourth hand gives second card to last hand and now has:", fourthHand,)
print ("Last hand now has:", lastHand,)
fourthHand.give(card3, lastHand)
print ("Fourth hand gives third card to last hand and now has:", fourthHand,)
print ("Last hand now has:", lastHand,)
fourthHand.give(card4, lastHand)
print ("Fourth hand gives fourth card to last hand and now has:", fourthHand,)
print ("Last hand now has:", lastHand,)
fourthHand.give(card5, lastHand)
print ("Fourth hand gives last card to last hand and now has:", fourthHand,)
print ("Last hand now has:", lastHand,)
print("\n")
def main():
while True :
print ("Do you want to pass cards? Press y or yes")
print("\n")
ans = input ()
passAgain(ans)
main()
// Hex2Binary Method
private string DEtoBinary(string HexDE)
{
string deBinary = "";
for (int I = 0; I <= 15; I++)
{
deBinary = deBinary + Hex2Binary(HexDE.Substring(I, 1));
}
return deBinary;
}
但是当我用C语言写作时，我接受如下所示的论证
private string Hex2Binary(string DE)
{
string myBinary = "";
switch (DE)
{
case "0":
myBinary = "0000";
break;
case "1":
myBinary = "0001";
break;
.
.
.
}
}
我收到错误了 切换数量不是整数。
答案 0 :(得分：1)
C＆C的开关仅适用于整数。在您的情况下，您似乎可以将开关arg转换为整数：
#include <stdlib> // for strtol
/* char* is a more typical string representation than char[] */
char *Hex2Binary(char* DE)
{
char *myBinary;
long de_as_long = strtol(DE, NULL, 16);
switch (de_as_long)
{
case 0:
myBinary = "0000";
break;
/* ... */
仅当DE的所有可能值都可以转换为整数时才有效。
答案 1 :(得分：0)
switch（）只接受整数。
你必须传递switch的整数而不是字符数组。
DE是一个字符数组。改变它以给出你想传递给开关的位置或整数。
答案 2 :(得分：0)
C不允许您打开char数组或字符串，但它确实允许您打开char s：
switch(DE[0]) {
case '0':
myBinary = "0000";
break;
case '1':
myBinary = "0001";
break;
/* ... */
}
但实际上，有一种更简单，更简洁的方法：
long val = strtol(DE, NULL, 16);
char myBinary[5] = {"01"[(val >> 3) & 1],
"01"[(val >> 2) & 1],
"01"[(val >> 1) & 1],
"01"[val & 1],
'\0' /* null terminator */
};
你可以使用循环来进一步简化这一过程。