toString()不适用于超类和子类

时间:2015-10-29 02:43:14

标签: java arrays loops override tostring

我在使用toString()方法正确显示时遇到问题。我在每个子类中重载它,我在main方法中调用它。我得到了所需输出的开头,但之后我得到的只是一个哈希。我也试图使用这个toString()方法显示数组的结果。

    //main method

    public class PublicationArray
{
public static void main(String[] args)
{
  Publication[] publications = new Publication[10];

  publications[0] = new Magazine("American Fisherman", 2.0, 100);      
  publications[1] = new Book("C++ Programming", 25.0, 70);
  publications[2] = new Magazine("Time", 1.5, 100);
  publications[3] = new Book("Morning Dove", 15.0, 39);
  publications[4] = new Magazine("Nerd", 3.0, 10);
  publications[5] = new Book("Walking and Chewing Gum for Dummies",14.0,40);
  publications[6] = new Magazine("New Yorker", 2.25, 28);
  publications[7] = new Book("J++ Programming", 30.0, 55);
  publications[8] = new Magazine("Devorced", 1.75, 33);
  publications[9] = new Book("Doing Nothing for Dummies", 10.0, 10);

  for(int i = 0; i < publications.length; i++)
  {
     System.out.println("Publication [" + i + "] is " + publications.toString());
  }


}
}


   //one of the subclasses, the other is identical except for the formula

public class Magazine extends Publication
{
public Magazine(String title, double cost, int quantity)
{
  super(title, cost, quantity);
}

String month;

public void setMonth(String pubMonth)
{
  month = pubMonth;
}
@Override
public double setPrice()
{
  double price = cost * 1.6;
  return price;
} 

@Override
public String toString()
{
  String display = "Title " + title + ",Price " + setPrice() +
     ", Cost " + cost + ", Quantity " + quantity;
  return display;
}
}



//Output

Publication [0] is Title ,Price 0.0, Cost 0.0, Quantity 0
Publication [1] is Title ,Price 0.0, Cost 0.0, Quantity 0
Publication [2] is Title ,Price 0.0, Cost 0.0, Quantity 0
Publication [3] is Title ,Price 0.0, Cost 0.0, Quantity 0
Publication [4] is Title ,Price 0.0, Cost 0.0, Quantity 0
Publication [5] is Title ,Price 0.0, Cost 0.0, Quantity 0
Publication [6] is Title ,Price 0.0, Cost 0.0, Quantity 0
Publication [7] is Title ,Price 0.0, Cost 0.0, Quantity 0
Publication [8] is Title ,Price 0.0, Cost 0.0, Quantity 0
Publication [9] is Title ,Price 0.0, Cost 0.0, Quantity 0

public abstract class Publication
{
String title = "";
double cost;
int quantity;

//Constructor
public Publication(String pubTitle, double pubCost, int pubQuantity)
{
  pubTitle = title;
  pubCost = cost;
  pubQuantity = quantity;
} 

//Set Methods
public void setTitle(String pubTitle)
{
  title = pubTitle;
}
public void setCost(double pubCost)
{
  cost = pubCost;
}
public void setQuantity(int pubQuantity)
{
  quantity = pubQuantity;
}

//Get Methods
public String getTitle()
{
  return title;
}
public double getCost()
{
  return cost;
}
public int getQuantity()
{
  return quantity;
}

public abstract double setPrice();


}

1 个答案:

答案 0 :(得分:1)

这是因为在数组上使用<Match ContentType="Page"> <Match DisplayType="Detail"> <Match Path="~/"> ... </Match> </Match> </Match> 方法会为您提供该数组的内存地址。您希望在自定义toString()方法中使用Arrays.toString(publications)

此外,您循环显示数组中的每个对象,但打印整个数组而不是单个实例:

toString()

如果您的输出问题仅为零,请确保超类中的变量为for(int i = 0; i < publications.length; i++) { System.out.println("Publication [" + i + "] is " + publications[i].toString()); } protected。然后在您的子类'public方法中使用toString()关键字访问它们:

this

您还应该使用public String toString() { String display = "Title " + this.title + ",Price " + setPrice() + ", Cost " + this.cost + ", Quantity " + this.quantity; return display; } 关键字访问this方法中的cost

修改

将零作为输出的问题可能是由于setPrice()类中的构造函数。您正在以错误的方式分配变量。它应该是这样的:

Publication