我正在努力教自己如何编写简单的文字游戏。我找到了一个YouTube教程,正在通过Der Kerker工作。我遇到的一个问题是他的最终代码与他在视频中所做的不符,所以我被卡住了。
这是我的问题:
当您加载游戏时,命令“take sword”和“help”都按设计工作。但是,如果你输入乱码或无法识别的命令,游戏应该说“我不明白......”
现在,它只清除输入框但实际上并没有运行命令。
这是我的游戏小提琴:
https://jsfiddle.net/megler/hv7hqp1e/
目标是,如果玩家输入无法识别的命令,它只会说“我不明白”。
这是JS:
//Check To See If True Function
var check = false;
// Been To Room Variables
var beenToCorridor = true;
//
//Inventory
var sword = false;
//
//Current Room
var currentRoom = "nCorridor";
$(document).ready(function() {
$("form").submit(function() {
var input = $("#commandLine").val();
function check() {
check = true;
}
if (input == "help") {
$("#messageHelp")
.clone()
.insertBefore("#placeholder")
.fadeIn(1000);
check();
}
if (input == "take sword" && currentRoom == "nCorridor") {
$("<p>You picked up a sword.</p>")
.hide()
.insertBefore("#placeholder")
.fadeIn(1000);
check();
}
else if (input == "take sword" && currentRoom != "nCorridor") {
$("<p>The sword is not here.</p>")
.hide()
.insertBefore("#placeholder")
.fadeIn(1000);
check();
}
else if (check == false) {
$("<p>I don't understand " + input + ".</p>")
.hide()
.insertBefore("#placeholder")
.fadeIn(1000);
}
$("#commandLine").val("");
});
});
希望这是有道理的。
答案 0 :(得分:1)
我认为这就是你想要的:
代码替换:
else if (input != "take sword" && input != "help") {
$("<p>I don't understand " + input + ".</p>").hide().insertBefore("#placeholder").fadeIn(1000);
}
<强>段:强>
//Check To See If True Function
var check = false;
// Been To Room Variables
var beenToCorridor = true;
//
//Inventory
var sword = false;
//
//Current Room
var currentRoom = "nCorridor";
$(document).ready(function() {
$("form").submit(function() {
var input = $("#commandLine").val();
function check() {
check = true;
}
if (input == "help") {
$("#messageHelp").clone().insertBefore("#placeholder").fadeIn(1000);
check();
}
if (input == "take sword" && currentRoom == "nCorridor") {
$("<p>You picked up a sword.</p>").hide().insertBefore("#placeholder").fadeIn(1000);
check();
}
else if (input == "take sword" && currentRoom != "nCorridor") {
$("<p>The sword is not here.</p>").hide().insertBefore("#placeholder").fadeIn(1000);
check();
}
else if (input != "take sword" && input != "help") {
$("<p>I don't understand " + input + ".</p>").hide().insertBefore("#placeholder").fadeIn(1000);
}
else
{
return false;
}
$("#commandLine").val("");
});
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<body>
<div id="console">
<p id="message_startGame">Welcome to my game!</p>
<p id="area_northCorridor">You are in the North Corridor. There is a sword on the ground.</p>
<p id="messageHelp" style = "display: none;">Here is a list of commands</p>
<!-- PLACEHOLDER: THIS IS WHERE EVERYTHING WILL BE INSERTED BEFORE
--->
<div id="placeholder"></div>
<form onsubmit="return false;">
<input type = "text" size ="50" autofocus="autofocus" id="commandLine">
</form>
</div>
</body>
&#13;
答案 1 :(得分:0)
为检查变量使用不同的名称。如果,您还应该将最后的分开。
//Check To See If True Function
var _check = false;
// Been To Room Variables
var beenToCorridor = true;
//
//Inventory
var sword = false;
//
//Current Room
var currentRoom = "nCorridor";
$(document).ready(function() {
$("form").submit(function() {
var input = $("#commandLine").val();
function check() {
_check = true;
}
if (input == "help") {
$("#messageHelp")
.clone()
.insertBefore("#placeholder")
.fadeIn(1000);
check();
}
if (input == "take sword" && currentRoom == "nCorridor") {
$("<p>You picked up a sword.</p>")
.hide()
.insertBefore("#placeholder")
.fadeIn(1000);
check();
}
else if (input == "take sword" && currentRoom != "nCorridor") {
$("<p>The sword is not here.</p>")
.hide()
.insertBefore("#placeholder")
.fadeIn(1000);
check();
}
if (_check == false) {
$("<p>I don't understand " + input + ".</p>")
.hide()
.insertBefore("#placeholder")
.fadeIn(1000);
}
$("#commandLine").val("");
});
});
答案 2 :(得分:0)
你应该
var check = false;
,否则if条件永远不会通过if ... else if ...
支票列表中添加其他内容。以下是更正后的代码:
$(document).ready(function () {
$("form").submit(function () {
var input = $("#commandLine").val();
// INITIALIZE CHECK VARIABLE HERE
var check = false;
function check() {
check = true;
}
if (input == "help") {
$("#messageHelp").clone().insertBefore("#placeholder").fadeIn(1000);
check();
}
// NEEDS AN ADDITIONAL ELSE HERE TO PREVENT DOUBLE MESSAGE AFTER HELP
else if (input == "take sword" && currentRoom == "nCorridor") {
$("<p>You picked up a sword.</p>").hide().insertBefore("#placeholder").fadeIn(1000);
check();
} else if (input == "take sword" && currentRoom != "nCorridor") {
$("<p>The sword is not here.</p>").hide().insertBefore("#placeholder").fadeIn(1000);
check();
} else if (check == false) {
$("<p>I don't understand " + input + ".</p>").hide().insertBefore("#placeholder").fadeIn(1000);
}
$("#commandLine").val("");
});
});
答案 3 :(得分:0)
每次提交表单时,都会将check变量重置为false,因此每次调用表单时都要从一个干净的slate中取出t = tart。同时将函数'check'重命名为'setChecked',以免引起全局变量和本地函数名之间的混淆。
$("form").submit(function() {
check = false;
function setChecked() {
check = true;
}
if (input == "help") {
setChecked();
}
//etc...
}
答案 4 :(得分:0)
这是因为你重新定义了检查&#39;作为一种功能,所以它不再等于假。
解决方案是使用另一个名称作为布尔值,例如&#39; ischeck&#39;,如下所示:
//Check To See If True Function
var ischeck = false;
// Been To Room Variables
var beenToCorridor = true;
//
//Inventory
var sword = false;
//
//Current Room
var currentRoom = "nCorridor";
$(document).ready(function() {
$("form").submit(function() {
var input = $("#commandLine").val();
function check() {
ischeck = true;
}
if (input == "help") {
$("#messageHelp").clone().insertBefore ("#placeholder").fadeIn(1000);
check();
}
if (input == "take sword" && currentRoom == "nCorridor") {
$("<p>You picked up a sword.</p>").hide().insertBefore ("#placeholder").fadeIn(1000);
check();
}
else if (input == "take sword" && currentRoom != "nCorridor") {
$("<p>The sword is not here.</p>").hide().insertBefore("#placeholder").fadeIn(1000);
check();
}
else if (ischeck == false) {
$("<p>I don't understand " + input + ".</p>").hide().insertBefore("#placeholder").fadeIn(1000);
}
$("#commandLine").val("");
});
});