Question

认为我必须遗漏一些东西，但我没有检查的调试功能。 Web应用程序通过socket.io将数据传递给node.js服务器，但不会发回任何内容。

server.js

// Load required modules
var http    = require("http");              // http server core module
var express = require("express");           // web framework external module
var io      = require("socket.io");         // web socket external module
var easyrtc = require("easyrtc");           // EasyRTC external module

// Setup and configure Express http server. Expect a subfolder called      "static" to be the web root.
var httpApp = express();
httpApp.use(express.static(__dirname + "/static/"));

// Start Express http server on port 8080
var webServer = http.createServer(httpApp).listen(8080);

// Start Socket.io so it attaches itself to Express server
var socketServer = io.listen(webServer, {"log level":1});

 // Start EasyRTC server
 var rtc = easyrtc.listen(httpApp, socketServer);

easyrtc.events.on('get_candy', function(easyrtc) {
  easyrtc.events.emit('did it');
});

file.js

function joined_room() {
easyrtc.sendServerMessage('get_candy', {candy_name:'mars'},
        function(msgType, msgData ) {
           console.log("got candy count of " + msgData.barCount);
        },
        function(errorCode, errorText) {
           console.log("error was " + errorText);
        });
}

easyrtc.setServerListener( function(msgType, msgData, targeting) {
    console.log("The Server sent the following message " + JSON.stringify(msgData));
}, 'get_candy');

Answer 1

几个月前我遇到了同样的问题，现在我的解决方案是在服务器上重用websocket：在客户端：

var socket = io.connect('http://' + document.domain + ':' + location.port);
easyrtc.useThisSocketConnection(socket);

在服务器端：

var io      = require("socket.io");         // web socket external module
var easyrtc = require("easyrtc");           // EasyRTC external module

var httpApp = express();
httpApp.use(express.static(__dirname + "/static/"));

// Start Express http server on port 8080
var webServer = http.createServer(httpApp).listen(8080);

// Start Socket.io so it attaches itself to Express server
var socketServer = io.listen(webServer);

var rtc = easyrtc.listen(webServer, io, null, function(err, rtcRef) {
  rtcRef.events.on('roomCreate', function(appObj, creatorConnectionObj, roomName, roomOptions, callback) {
    console.log('roomCreate fired!');
  });
});

此剪辑允许您重新使用websocket进行easyRTC。 RTC和其他人的签名消息可以使用相同的websocket。

Easyrtc通过websockets进行数据交换

1 个答案: