Question

抱歉我的英文。每个月我都去赌场玩，一个月一次。我的决定标准：用随机模块查找在赌场玩的日和周，只有一个例外，不接受随机模块上个月和周日播放。例如，如果我去了十月十四日，十一月的那一天应该是任何一天但不是十四日。这是我的代码：例如，如果我输入相同的数字“2”，程序不会消除我上个月的数字“2”。请帮忙。

import random

zz = raw_input ("Please enter the last week number: ")

fx = int(zz)

print fx



week_randoms=[]

gg = week_randoms


for i in range (4):

    gg = week_randoms

    gg.append(random.randrange(1,5))

print gg

hh = gg[0:1]


if fx != hh:

    print "You got your number baby", hh

else:
    print  "Run this program again"

Answer 1

试试这个，它将为您提供未来12个月的日期。它将排除第29-31天，所以我们没有任何想象的日子，比如2月31日。

import random
days = range(1,29)
months = ['January','February','March','April','May','June','July','August','September','October','November','December']
for a in months:
    b = random.choice(days)
    days.remove(b)
    print "Go on Day " + str(b) + " of the month of " + a " "."

Answer 2

您可以跟踪所选的最后一天的数字，并确保不再选择它。今年（或任何其他闰年）：

import random
months = ['January','February','March','April','May','June','July','August','September','October','November','December']
days_in_months = [31,29,31,30,31,30,31,31,30,31,30,31]
last_day_number = None
for month,ndays in zip(months,days_in_months):
    while True:
        day_number = random.randint(1,ndays)
        if day_number != last_day_number:
            break
    last_day_number = day_number
    print(day_number, month, '2016')

e.g。

28 January 2016
22 February 2016
21 March 2016
13 April 2016
21 May 2016
24 June 2016
25 July 2016
9 August 2016
16 September 2016
12 October 2016
5 November 2016
7 December 2016

祝你好运！

Answer 3

xnx实施的略微修改版本：

import calendar
import random

last_pick = None

for i in range(1, 13):
    month = calendar.month_name[i]
    _, end = calendar.monthrange(2016, i)

    while True:
        day = random.randint(1, end)

        if day != last_pick:
            break

    last_pick = day

    print(day, month, 2016)

赌场 - 随意运气 - Python

3 个答案: