所以我试图制作一个程序主要是出于好奇和一点点我的学习!但我遇到了这个问题。当我尝试在另一个中使用switch语句时,如果我选择switch语句所在的情况,我的程序将变为默认值。
printf("Please enter the first character of the thing you want to get perimeter and area of off: ");
scanf_s("%c", &holder);
switch (toupper(holder))
{
case 'C':
printf("Please enter the radius of the circle: ");
scanf_s("%d", &a);
if (a <= 0)
printf("Please enter a positive radius!\n");
else
{
perimeter = 2 * PI * a;
area = PI * a * a;
printf("Perimeter of the circle is %.2f\n", perimeter);
printf("Area of the circle is %.2f\n", area);
}
break;
case 'R':
printf("Please enter the two sides of the rectangle!\n");
scanf_s("%d %d", &a, &b);
if (a <= 0 || b <= 0)
printf("Please enter positive numbers as sides values!\n");
else
{
perimeter = a + a + b + b;
area = a * b;
printf("Perimeter of the rectangle is %.2f", perimeter);
printf("Area of the rectangle is %.2f", area);
}
break;
case 'T':
printf("Please enter a for calculation using 3 sides and b for 2 sides and the angle between them!");
scanf_s("%c", &e);
switch (e)
{
case 'a':
printf("Please enter the three sides values!\n");
scanf_s("%d %d %d", &a, &b, &c);
if (a <= 0 || b <= 0 || c <= 0 || a >= b + c || b >= a + c || c >= a + b || a < abs(b - c) || b < abs(a - c) || c < abs(a - b))
printf("Please enter viable side values!\n");
else
{
perimeter = a + b + c;
d = perimeter / 2;
area = sqrt(d * (d - a) * (d - b) * (d - c));
printf("Triangles perimeter is %2.f\n", perimeter);
printf("Triangles area is %2.f\n", area);
}
break;
case 'b':
printf("Please enter 2 sides and the degree between them!\n");
scanf_s("%d %d %d", &a, &b, &c);
c1 = PI / 180 * c;
perimeter = (a * a) + (b * b) - (2 * a * b * cos(c1));
area = (1 / 2) * a * b * sin(c1);
printf("Triangles perimeter is %2.f\n", perimeter);
printf("Triangles area is %2.f\n", area);
break;
}
default:
printf("Unknown character!\n");
}
system("pause");
}
答案 0 :(得分:1)
你必须给出的第一个scanf输入是T\n
(因为你给了T后跟输入键 - 在linux上是\n
- 假设它是linux)
所以它目前在stdin缓冲区中不是一个而是两个字符。因此,当您扫描字符'e'
时,它实际上读取'\n'
而不是用户下一步输入的内容,因此在内部开关中进入默认情况。
编辑:由于内置交换机中没有默认情况,因此\n
的情况不会在任何地方处理。这也意味着没有为外部开关执行break
,因此将执行包括默认在内的所有后续情况,这就是您获得Unknown Character
因此,如果您确定总是按下回车键,则可以在取第二个字符之前执行getchar()
。
getchar(); //removes \n from stdin
scanf_s("%c", &e);